Wildlife biologists inspect 150 deer taken by hunters and find 30 of them carrying Lyme disease ticks. Use Rguroo to answer the following questions. Formulas: For 94% confidence level z* =1.88, margin of error E = 2* p(1-p) n = ô · (1 − p ) ( #)² V 76 a) The point estimate is ô: = place, if needed. b) The standard error of the sample proportion is s. e. (p) Round your answer to four decimal places. . Round to one decimal c) The margin of error with confidence level of 94% is E= . Round your answer to four decimal places. =
Wildlife biologists inspect 150 deer taken by hunters and find 30 of them carrying Lyme disease ticks. Use Rguroo to answer the following questions. Formulas: For 94% confidence level z* =1.88, margin of error E = 2* p(1-p) n = ô · (1 − p ) ( #)² V 76 a) The point estimate is ô: = place, if needed. b) The standard error of the sample proportion is s. e. (p) Round your answer to four decimal places. . Round to one decimal c) The margin of error with confidence level of 94% is E= . Round your answer to four decimal places. =
A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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![Wildlife biologists inspect 150 deer taken by hunters and find 30
of them carrying Lyme disease ticks.
Use Rguroo to answer the following questions.
Formulas: For 94% confidence level z* = 1.88, margin of
p(1-p)
error E= 2*· 1/
n = ô · (1 − p ) ( #)²
76
a) The point estimate is ô:
=
place, if needed.
=
b) The standard error of the sample proportion is s. e. (p)
Round your answer to four decimal places.
. Round to one decimal
c) The margin of error with confidence level of 94% is E=
. Round your answer to four decimal places.
d) We are 94% confident that the true population proportion of
deer that carry Lyme disease ticks is between
% and
%. Calculate your answer to four decimal places
then write the answer in percentage.
e) If we decrease the confidence level to 90%, the interval gets
(write "wider" or "narrower")
f) If the scientists want to cut the margin of error, E to ±0.03 the
number of deer that must be inspected is
Round
your answer to the next whole number and consider the same
94% C.I.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff5f3d717-430b-4c17-9d2a-b85bcd526d4a%2Fe064fa79-8fce-4e7c-9c36-dabb7c30a845%2Frjn1xbs_processed.png&w=3840&q=75)
Transcribed Image Text:Wildlife biologists inspect 150 deer taken by hunters and find 30
of them carrying Lyme disease ticks.
Use Rguroo to answer the following questions.
Formulas: For 94% confidence level z* = 1.88, margin of
p(1-p)
error E= 2*· 1/
n = ô · (1 − p ) ( #)²
76
a) The point estimate is ô:
=
place, if needed.
=
b) The standard error of the sample proportion is s. e. (p)
Round your answer to four decimal places.
. Round to one decimal
c) The margin of error with confidence level of 94% is E=
. Round your answer to four decimal places.
d) We are 94% confident that the true population proportion of
deer that carry Lyme disease ticks is between
% and
%. Calculate your answer to four decimal places
then write the answer in percentage.
e) If we decrease the confidence level to 90%, the interval gets
(write "wider" or "narrower")
f) If the scientists want to cut the margin of error, E to ±0.03 the
number of deer that must be inspected is
Round
your answer to the next whole number and consider the same
94% C.I.
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