wiew Policies Current Attempt in Progress A helicopter is using a circular steel cable to lift a m = 2100-kg jeep. The unstretched length of the cable is L= 16 m, and its radius is r - 5.0 x 10° m. By what amount does the cable stretch when the jeep is hoisted straight upward with an acceleration of a, = +2.95 m/s?? Young's modulus for steel is Y = 2.0x 1011 N/m². 2.95 mis? (b) Free-body diagram for the jeep (a) (a) The jeep applies a force – F to the lower end of the cable, thereby stretching it. (b) The free-body diagram for the jeep, showing the two forces acting on it. Number Units

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### Week 4 Homework

#### Question 15 of 15

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### Current Attempt in Progress

A helicopter is using a circular steel cable to lift a \( m = 2100 \)-kg jeep. The unstretched length of the cable is \( L = 16 \) m, and its radius is \( r = 5.0 \times 10^{-3} \) m. By what amount does the cable stretch when the jeep is hoisted straight upward with an acceleration of \( a_y = +2.95 \) m/s\(^2\)? Young's modulus for steel is \( Y = 2.0 \times 10^{11} \) N/m\(^2\).

#### Diagram Explanation

- **(a)** The jeep applies a force \( -\mathbf{F} \) to the lower end of the cable, thereby stretching it.
- **(b)** The free-body diagram for the jeep, showing the two forces acting on it.
  - The upward force \( \mathbf{F} \).
  - The weight of the jeep \( \mathbf{W} \).
  - The acceleration \( a_y = +2.95 \) m/s\(^2\).

\( \uparrow +y \)

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| Number | Units |
| ------ | ----- |
|        |       |

#### eTextbook and Media

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This problem involves understanding the principles of physics, specifically the stretching of materials under force. By calculating the stretch of the cable, students will apply concepts from mechanics and material science, such as force, acceleration, and Young's modulus.
Transcribed Image Text:### Week 4 Homework #### Question 15 of 15 --- ### Current Attempt in Progress A helicopter is using a circular steel cable to lift a \( m = 2100 \)-kg jeep. The unstretched length of the cable is \( L = 16 \) m, and its radius is \( r = 5.0 \times 10^{-3} \) m. By what amount does the cable stretch when the jeep is hoisted straight upward with an acceleration of \( a_y = +2.95 \) m/s\(^2\)? Young's modulus for steel is \( Y = 2.0 \times 10^{11} \) N/m\(^2\). #### Diagram Explanation - **(a)** The jeep applies a force \( -\mathbf{F} \) to the lower end of the cable, thereby stretching it. - **(b)** The free-body diagram for the jeep, showing the two forces acting on it. - The upward force \( \mathbf{F} \). - The weight of the jeep \( \mathbf{W} \). - The acceleration \( a_y = +2.95 \) m/s\(^2\). \( \uparrow +y \) --- | Number | Units | | ------ | ----- | | | | #### eTextbook and Media --- This problem involves understanding the principles of physics, specifically the stretching of materials under force. By calculating the stretch of the cable, students will apply concepts from mechanics and material science, such as force, acceleration, and Young's modulus.
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