Java **Title: Understanding Infinite Recursion in Java Methods****Question:** Why might the following method have infinite recursion?```javapublic void infiniteRecursion(int n) { if (n > 0) { System.out.println("here"); infiniteRecursion(n-1); } else if(n < 0){ System.out.println("here"); infiniteRecursion(n+1); } else { System.out.println("here"); }}```**Explanation:** The code snippet is a method designed to print "here" and then call itself recursively. It has three main conditions based on the value of `n`:1. **If `n` is greater than 0**: It decrements `n` and calls the method again.2. **If `n` is less than 0**: It increments `n` and calls the method again.3. **If `n` is equal to 0**: It prints "here" without further recursive calls, serving as a base case.**Possible Answers:**- **Because there is no base case**- **Because the base case will never be true**- **None of these is correct, there is no infinite recursion in this method**- **Because the recursive call does not move the parameter closer to the base case****Correct Answer:** The base case is `n == 0`, which prevents further recursion. However, if the initial value of `n` is not zero, the recursive call should move `n` closer to this base case. The provided method implements this logic correctly by decrementing `n` when `n > 0` and incrementing when `n < 0`. Thus, infinite recursion should not occur if `n` is finite and properly increments or decrements towards zero.

Let assume n = 2 First call -> infiniteRecursion(2) Here 2 is greater than 0, so if section is…

Why might the following method have infinite recursion? public void infiniteRecursion(int n) { if (n > 0) { } System.out.println("here"); infiniteRecursion(n-1); } else if(n < 0) { System.out.println("here"); infiniteRecursion(n+1); System.out.println("here"); } else { } Because there is no base case Because the base case will never be true None of these is correct, there is no infinite recursion in this method Because the recursive call does not move the parameter closer to the base case

Why might the following method have infinite recursion? public void infiniteRecursion(int n) { if (n > 0) { } System.out.println("here"); infiniteRecursion(n-1); } else if(n < 0) { System.out.println("here"); infiniteRecursion(n+1); System.out.println("here"); } else { } Because there is no base case Because the base case will never be true None of these is correct, there is no infinite recursion in this method Because the recursive call does not move the parameter closer to the base case

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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