Why might the following method have infinite recursion? public void infiniteRecursion(int n) { if (n > 0) { } System.out.println("here"); infiniteRecursion(n-1); } else if(n < 0) { System.out.println("here"); infiniteRecursion(n+1); System.out.println("here"); } else { } Because there is no base case Because the base case will never be true None of these is correct, there is no infinite recursion in this method Because the recursive call does not move the parameter closer to the base case

Why might the following method have infinite recursion? public void infiniteRecursion(int n) { if (n > 0) { } System.out.println("here"); infiniteRecursion(n-1); } else if(n < 0) { System.out.println("here"); infiniteRecursion(n+1); System.out.println("here"); } else { } Because there is no base case Because the base case will never be true None of these is correct, there is no infinite recursion in this method Because the recursive call does not move the parameter closer to the base case

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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import java.util.Scanner; public class LabProgram { // Recursive method to draw the triangle public static void drawTriangle(int baseLength, int currentLength) { if (currentLength <= 0) { return; // Base case: stop when currentLength is 0 or negative } // Calculate the number of spaces needed for formatting int spaces = (baseLength - currentLength) / 2; if (currentLength == baseLength) { // If it's the first line, don't output spaces before the first '*' System.out.println("*".repeat(currentLength) + " "); } else { // Output spaces and asterisks System.out.println(" ".repeat(spaces) + "*".repeat(currentLength) + " "); } // Recursively call drawTriangle with the reduced currentLength drawTriangle(baseLength, currentLength - 2); } public static void drawTriangle(int baseLength) { drawTriangle(baseLength, baseLength); } public static…
import java.util.Scanner; public class LabProgram { // Recursive method to draw the triangle public static void drawTriangle(int baseLength, int currentLength) { if (currentLength <= 0) { return; // Base case: stop when currentLength is 0 or negative } // Calculate the number of spaces needed for formatting int spaces = (baseLength - currentLength) / 2; if (currentLength == baseLength) { // If it's the first line, don't output spaces before the first '*' System.out.println(" ".repeat(spaces) + "*".repeat(currentLength)); } else { // Output spaces and asterisks System.out.println(" ".repeat(spaces) + "*".repeat(currentLength)); } // Recursively call drawTriangle with the reduced currentLength drawTriangle(baseLength, currentLength - 2); } public static void drawTriangle(int baseLength) { drawTriangle(baseLength, baseLength); } public…
In Java Ackermann’s Function Ackermann’s function is a recursive mathematical algorithm that can be used to test how well a computer performs recursion. Write a method ackermann(m, n), which solves Ackermann’s function. Use the following logic in your method: If m = 0 then return n + 1 If n = 0 then return ackermann(m - 1, 1) Otherwise, return ackermann(m - 1, ackermann(m, n - 1)) Test your method in a program that displays the return values of the following method calls: ackermann(0, 0) ackermann(0, 1) ackermann(1, 1) ackermann(1, 2)ackermann(1, 3) ackermann(2, 2) ackermann(3, 2)
public class Recursive{ public static void main(String[] args){ System.out.println("Summation of System.out.println("Summation of 1 = "+summation(1)); System.out.println("Summation of 10 = "+summation(10)); System.out.println("Summation of System.out.println("Summation of 7 = "+summation(7)); 5 = "+summation(5)); 1 = "+summation(1)); System.out.println("The first position value in the Fibonacci Sequence is "+fibonacciSequence(1)); System.out.println("The third position value in the Fibonacci Sequence is "+fibonacciSequence(3)); System.out.println("The seventh position value in the Fibonacci Sequence is "+fibonacciSequence(7)); System.out.println("The twentith position value in the Fibonacci Sequence is "+fibonacciSequence(20)); } public static int summation(int n){ //TODO: Create a recursive method that will find the summation of n for all positive n return -1; } public static int fibonacciSequence(int positionN){ //TODO: Create a recursive method that will find the Nth position of the…
sum= 0; for (int i = 0; i 1) { sum++; i= 1/2; } = 2*log2 (n) We denote by Ta(n), Tb (n), Te(n) the running time of the three fragments. 1. Give evaluations for Ta(n), Tb (n), Te(n). 2. Is T(n) = O(Ta(n)) ? Answer YES or NO and justify your answer. 3. Is Te(n) = (Ta(n)) ? Answer YES or NO and justify your answer.
Solve in javaFX
Consider the recursive method myPrint: public void myPrint (int n) if (n < 10) System.out.print(n); else { int m = n % 10; %3D System.out.print (m) ; myPrint (n / 10); What is printed for the call myPrint (10)?
This method uses recursion to find the area of a triangle with a given width. public int getArea(){ if (width == 1) { return 1; } else { Triangle smallerTriangle = new Triangle(width - 1); int smallerArea = smallerTriangle.getArea(); return smallerArea + width; } Using this example, outline, but do not implement, a recursive solution for finding the smallest value in an array. For example, suppose we have an Integer array with elements [12, 15, 28, 32, 3, 7, 21]. Outline how we can use recursion to find the smallest element, 3, in the array.
b. Convert the following iteration into Recursion version: public void FO0( int n){ for (int i=n; i>=0;i--){ System.out.println(i*5); }}
Write a recursive method called digitCount() that takes two integers, n and m as a parameter and returns the number of digits in n that are equal to m. Assume that n≥0 and 0≤m≤9 Ex: If the input is: 34443215 4 3 import java.util.Scanner; public class LabProgram { /* TODO: Write recursive digitCount() method here. */ public static void main(String[] args) { Scanner scnr = new Scanner(System.in); int digits; int n= scnr.nextInt(); int m= scnr.nextInt(); digits = digitCount(n, m); System.out.println(digits); }}
recursive solution oddEvenMatchRec:the method takes an integer array as a parameter and returns a boolean. The method returns trueif every odd index contains an odd integer AND every even index contains aneven integer(0 is even). Otherwise it returns fals
Java - Write an iterative method that calculates the SUM of all integers between 1 and a given integer N (input into the method). Write a corresponding recursive solution. (return answer, don’t print)