Why is this the case: Recall that for x,yER, | x-y|E Rot, is the absoulate value of x-y. That is, 1x-y = {x-y Define the binary -(x-y). If x-y 20 If. х-ухо х-усо relation R on F xRy if |x-y| < 1 How can I proof transistixtx . R as follows: why is that, if x>y or y>x it will not be <1 can you explain with examples? Why not antisytric? Let, x, y be two element in R 1x-y1 <1, then | y-x1 <1. So, XRyYRX and thus R is Symmetric relation and not an relation. such that a antisymmetrik
Why is this the case: Recall that for x,yER, | x-y|E Rot, is the absoulate value of x-y. That is, 1x-y = {x-y Define the binary -(x-y). If x-y 20 If. х-ухо х-усо relation R on F xRy if |x-y| < 1 How can I proof transistixtx . R as follows: why is that, if x>y or y>x it will not be <1 can you explain with examples? Why not antisytric? Let, x, y be two element in R 1x-y1 <1, then | y-x1 <1. So, XRyYRX and thus R is Symmetric relation and not an relation. such that a antisymmetrik
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section: Chapter Questions
Problem 59RE
Related questions
Question
![Why is this the case:
Recall that for x,yER, | x-y|E Rot, is the
absoulate
value of x-y. That is,
1x-y = {x-y
Define the binary
-(x-y). If x-y 20
If. х-ухо
х-усо
relation
R on
F
xRy if |x-y| < 1
How can I proof transistixtx
.
R as follows:
why is that, if x>y or y>x it will not be <1 can you explain with examples? Why not antisxtric?
Let, x, y be two element in R
1x-y1 <1,
then | y-x1 <1.
So, XRyYRX and thus R is
Symmetric relation and not an
relation.
such that
a
antisymmetrik](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa1ab2968-d288-4fd8-b87c-74963c459231%2F858d15d8-96b9-4b67-a564-89225d234039%2F64mujso_processed.png&w=3840&q=75)
Transcribed Image Text:Why is this the case:
Recall that for x,yER, | x-y|E Rot, is the
absoulate
value of x-y. That is,
1x-y = {x-y
Define the binary
-(x-y). If x-y 20
If. х-ухо
х-усо
relation
R on
F
xRy if |x-y| < 1
How can I proof transistixtx
.
R as follows:
why is that, if x>y or y>x it will not be <1 can you explain with examples? Why not antisxtric?
Let, x, y be two element in R
1x-y1 <1,
then | y-x1 <1.
So, XRyYRX and thus R is
Symmetric relation and not an
relation.
such that
a
antisymmetrik
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