Why is there two values of 1.5? Where did the other one came from?

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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Why is there two values of 1.5? Where did the other one came from?
153.7
RAx ↑
RAY
152,09N T
划g N
12036N
Now usirg Fore and Momert
equilibruum equations
At suffert A end B t
EFX =0 RAX +4ax3 -120.36_132.ng TRey
B
EFyzo RAy + Rey -159.72+ 111.09
fis
EMA =° (momenf at A=o)
RBY X 30 + 141•09X7 – 4aX 3X(1s+1-5)– 159.79X4
RB4X {o =71.63 + 378 F 630.88
RBY X 1° = 239.25
RBy = 23.925N
%3D
how using equation Li) →
RA
152.09 + 120-36 – 126
%3D
= 147.26
using equntion lüv -
Ray + Roy = 159.72 – 311. 69
%3D
Ray
= 4P.63- RB
Ray = 48.63-23, §25
KBY= 23-9 5N)
%3D
(Ray = 24r705 N
Transcribed Image Text:153.7 RAx ↑ RAY 152,09N T 划g N 12036N Now usirg Fore and Momert equilibruum equations At suffert A end B t EFX =0 RAX +4ax3 -120.36_132.ng TRey B EFyzo RAy + Rey -159.72+ 111.09 fis EMA =° (momenf at A=o) RBY X 30 + 141•09X7 – 4aX 3X(1s+1-5)– 159.79X4 RB4X {o =71.63 + 378 F 630.88 RBY X 1° = 239.25 RBy = 23.925N %3D how using equation Li) → RA 152.09 + 120-36 – 126 %3D = 147.26 using equntion lüv - Ray + Roy = 159.72 – 311. 69 %3D Ray = 4P.63- RB Ray = 48.63-23, §25 KBY= 23-9 5N) %3D (Ray = 24r705 N
Through your solutions, prove that the support reactions are similar to the values shown below.
Rb = 23.927 N, Upward
Ray = 24.709 N, Upward
Rax = 147.267 N, Left
200 N
53
36
1.5
189 N
42 kN/m
3
B
4
3
3
Note: Uniform distributed load = 42 N/m, if you believe that the correct answer/s is/are not included
above, justify your answer.
Transcribed Image Text:Through your solutions, prove that the support reactions are similar to the values shown below. Rb = 23.927 N, Upward Ray = 24.709 N, Upward Rax = 147.267 N, Left 200 N 53 36 1.5 189 N 42 kN/m 3 B 4 3 3 Note: Uniform distributed load = 42 N/m, if you believe that the correct answer/s is/are not included above, justify your answer.
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