why is the x component of fbe not taken in the moment calculation at a? the x componebt is under the beam which not throught the line of action at a

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why is the x component of fbe not taken in the moment calculation at a?

the x componebt is under the beam which not throught the line of action at a

Еxample 2
The elevation and tilt angle of table AB are controlled by an operator's hand at point D. The table supports a box
weighing 40 N with center of gravity at point G. Determine the force the operator must apply to keep the table in
equilibrium, and determine the force supported by all members of the machine if the force applied by the
operator is vertical.
70 um
Ľ.
A
B.
20cm
Hand
30 um
- 25
40N
A,
Ax
FBE
Ay
FAE
Transcribed Image Text:Еxample 2 The elevation and tilt angle of table AB are controlled by an operator's hand at point D. The table supports a box weighing 40 N with center of gravity at point G. Determine the force the operator must apply to keep the table in equilibrium, and determine the force supported by all members of the machine if the force applied by the operator is vertical. 70 um Ľ. A B. 20cm Hand 30 um - 25 40N A, Ax FBE Ay FAE
FBE
Ax
42.9 cm
20 um
38cn
FBE
しっ
ÅBLU :
EMA-O: - (4ON)(21cn)+ (Fee) ()° cm)
FRE = 6 3.9 N
Ź Fx=0: Ax + FeE () -.
78
→ Ax = - 55.7 N
EFy= 0: Ag + Fee () -40N = → Ay - 18.7N
42.5
ACO :
EMc =0: Ax (20un) + Ay(30 cm)- (P)(2m) =
P- 32N
/
ÉFx=0:
(x- Ax = o →
Ax = -55,7N
EFy=0.
-A, +ら-P-o
:: Cy = 42.7 N
Transcribed Image Text:FBE Ax 42.9 cm 20 um 38cn FBE しっ ÅBLU : EMA-O: - (4ON)(21cn)+ (Fee) ()° cm) FRE = 6 3.9 N Ź Fx=0: Ax + FeE () -. 78 → Ax = - 55.7 N EFy= 0: Ag + Fee () -40N = → Ay - 18.7N 42.5 ACO : EMc =0: Ax (20un) + Ay(30 cm)- (P)(2m) = P- 32N / ÉFx=0: (x- Ax = o → Ax = -55,7N EFy=0. -A, +ら-P-o :: Cy = 42.7 N
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