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Why is the net area for AB (0.045-0.0102) * (0.012) ? Why is AB in tension and BC in compression

Why is the net area for AB (0.045-0.0102) * (0.012) ? Why is AB in tension and BC in compression

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Why is the net area for AB (0.045-0.0102) * (0.012) ? Why is AB in tension and BC in compression

Problem 1.60 1.60 Two horizontal 20 kN forces are applied to pin B of the assembly shown. Knowing that a pin of 20 mm diameter is used at each connection, de- termine the maximum value of the average normal stress (a) in link AB, (b) in link BC. 12 mn B Use joint B as free body. 45 mm 20 kN 20 kN 12 mm A 60° 40 kN 45 nim 45° Fec Fee 60° 450 40 EN. Law of Sines Force triangle FAB 40 Fee sin 60 sin 45° sin 95° = 28.4 kN Fec = 34.8 KN Link AB is a tension m ember Min imum section at pin Anet = (o-045-0:o2)(0.012) = 300xiom
Transcribed Image Text:Problem 1.60 1.60 Two horizontal 20 kN forces are applied to pin B of the assembly shown. Knowing that a pin of 20 mm diameter is used at each connection, de- termine the maximum value of the average normal stress (a) in link AB, (b) in link BC. 12 mn B Use joint B as free body. 45 mm 20 kN 20 kN 12 mm A 60° 40 kN 45 nim 45° Fec Fee 60° 450 40 EN. Law of Sines Force triangle FAB 40 Fee sin 60 sin 45° sin 95° = 28.4 kN Fec = 34.8 KN Link AB is a tension m ember Min imum section at pin Anet = (o-045-0:o2)(0.012) = 300xiom
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