Why is the force Fd pointing downwards? By force equilibrium, shouldnt  it be 3 + Fd = 9 Fd = 6kN, thus pointing upwards?

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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Why is the force Fd pointing downwards?

By force equilibrium, shouldnt  it be

3 + Fd = 9

Fd = 6kN, thus pointing upwards?

8.44 The steel pipe AB has a 72-mm outer diameter and a 5-mm wall thickness.
Knowing that the arm CDE is rigidly attached to the pipe, determine the principal
stresses, principal planes, and the maximum shearing stress at point H.
Use stress transformation eqns.
Fo
9- 3 = 6 kN b
%3D
%3D
To= (12 x10)(120 »10)
%3D
3 kN
%3D
1440
N.m
D
| 9 kN
120 mm
150 mm
120 mm
1440 N-m '6 kN 900 N.
At the section contain ing point H,
P=0, V= 6 kN,
(6x103)(150x10')
E
T = 1440 N.m
%3D
900 Nom
do = 72 mm C, d. - 36 mn C; = Co-t = 31 mm
T7 (C*- C;* ) I - (c.*-c:") J = 2I
For hadf-pipe,
At point H
Q = (c.³ - c.' )
%3D
VQ
It
TC
= O
55.0 MPa
55.0 MPa
エ
Transcribed Image Text:8.44 The steel pipe AB has a 72-mm outer diameter and a 5-mm wall thickness. Knowing that the arm CDE is rigidly attached to the pipe, determine the principal stresses, principal planes, and the maximum shearing stress at point H. Use stress transformation eqns. Fo 9- 3 = 6 kN b %3D %3D To= (12 x10)(120 »10) %3D 3 kN %3D 1440 N.m D | 9 kN 120 mm 150 mm 120 mm 1440 N-m '6 kN 900 N. At the section contain ing point H, P=0, V= 6 kN, (6x103)(150x10') E T = 1440 N.m %3D 900 Nom do = 72 mm C, d. - 36 mn C; = Co-t = 31 mm T7 (C*- C;* ) I - (c.*-c:") J = 2I For hadf-pipe, At point H Q = (c.³ - c.' ) %3D VQ It TC = O 55.0 MPa 55.0 MPa エ
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