Why is the EA, for Si greater than the EA¡ for P? EA1 decreases from left to right across a period. The electron added to P must be paired with another electron. The electron added to Si must be paired with another electron. The electron added to Si goes into a higher subshell. The electron added to P goes into a higher subshell.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Question:** Why is the \( EA_1 \) for Si greater than the \( EA_1 \) for P?

1. \( EA_1 \) decreases from left to right across a period.
2. The electron added to P must be paired with another electron.
3. **The electron added to Si must be paired with another electron.**
4. The electron added to Si goes into a higher subshell.
5. The electron added to P goes into a higher subshell.

The correct answer is option 3.
Transcribed Image Text:**Question:** Why is the \( EA_1 \) for Si greater than the \( EA_1 \) for P? 1. \( EA_1 \) decreases from left to right across a period. 2. The electron added to P must be paired with another electron. 3. **The electron added to Si must be paired with another electron.** 4. The electron added to Si goes into a higher subshell. 5. The electron added to P goes into a higher subshell. The correct answer is option 3.
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