why is the deflection of the plate is in the coordinate 'c' direction instead of 'b' since the force P is applied in  the 'b' direction? Also, why is the shear force on the front of the plate pointing right and the back pointing left? can it be the opposite where the front of the plate will have a shear force pointing left at the front and pointing right at the back

Elements Of Electromagnetics
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why is the deflection of the plate is in the coordinate 'c' direction instead of 'b' since the force P is applied in  the 'b' direction?

Also, why is the shear force on the front of the plate pointing right and the back pointing left? can it be the opposite where the front of the plate will have a shear force pointing left at the front and pointing right at the back?

PROBLEM 2.79 Two blocks of rubber with a modulus of rigidity G = 12 MPa are bonded to rigid
supports and to a plate AB. Knowing that c = 100 mm and P = 40 kN, determine the smallest
dimensions a and b of the blocks if the shearing stress in the rubber is not to exceed 1.4 MPa
and the deflection of the plate is to be at least 5 mm.
%3D
d = Smm
P/2
B.
a ?
P/2
P/2
P
P/2
P.
= 40 kN
Shearing strain:
y = 8/ a = t/ G
a = G 8/ t= 43 mm
=100mm
Note: tan y = Y
(for small )
Transcribed Image Text:PROBLEM 2.79 Two blocks of rubber with a modulus of rigidity G = 12 MPa are bonded to rigid supports and to a plate AB. Knowing that c = 100 mm and P = 40 kN, determine the smallest dimensions a and b of the blocks if the shearing stress in the rubber is not to exceed 1.4 MPa and the deflection of the plate is to be at least 5 mm. %3D d = Smm P/2 B. a ? P/2 P/2 P P/2 P. = 40 kN Shearing strain: y = 8/ a = t/ G a = G 8/ t= 43 mm =100mm Note: tan y = Y (for small )
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