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Why is methanol chosen as the solvent for recrystallization? What would happen if the student uses dichloromethane instead?

Why is methanol chosen as the solvent for recrystallization? What would happen if the student uses dichloromethane instead?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Why is methanol chosen as the solvent for recrystallization? What would happen if the student uses dichloromethane instead?

In the current experiment, we will use a different electrophile (the tert-butyl cation) to alkylate 1,4-dimethoxybenzene. This is a Friedel-Crafts Alkylation reaction. **Diagram Explanation:** - **Left Side (Reactants):** - The reactant is 1,4-dimethoxybenzene, which is a benzene ring with two methoxy groups (OCH₃) attached at the 1 and 4 positions. One methoxy group is depicted on the top right, and the other on the bottom left of the benzene ring. - **Middle (Reaction Conditions):** - Over the arrow, (CH₃)₃COH is shown, indicating that tert-butyl alcohol is used. - Below the arrow, CH₃COOH/H₂SO₄ is noted, showing that acetic acid and sulfuric acid are used as the reaction conditions. - **Right Side (Product):** - The product is a benzene ring with methoxy groups (OCH₃) and two tert-butyl groups ((CH₃)₃C) attached at the 1 and 4 positions. The tert-butyl groups are depicted as (H₃C)₃C, placed above the top right and bottom right of the benzene ring. The diagram illustrates the Friedel-Crafts Alkylation process where the tert-butyl cation acts as the electrophile to alkylate 1,4-dimethoxybenzene.
Transcribed Image Text:In the current experiment, we will use a different electrophile (the tert-butyl cation) to alkylate 1,4-dimethoxybenzene. This is a Friedel-Crafts Alkylation reaction. **Diagram Explanation:** - **Left Side (Reactants):** - The reactant is 1,4-dimethoxybenzene, which is a benzene ring with two methoxy groups (OCH₃) attached at the 1 and 4 positions. One methoxy group is depicted on the top right, and the other on the bottom left of the benzene ring. - **Middle (Reaction Conditions):** - Over the arrow, (CH₃)₃COH is shown, indicating that tert-butyl alcohol is used. - Below the arrow, CH₃COOH/H₂SO₄ is noted, showing that acetic acid and sulfuric acid are used as the reaction conditions. - **Right Side (Product):** - The product is a benzene ring with methoxy groups (OCH₃) and two tert-butyl groups ((CH₃)₃C) attached at the 1 and 4 positions. The tert-butyl groups are depicted as (H₃C)₃C, placed above the top right and bottom right of the benzene ring. The diagram illustrates the Friedel-Crafts Alkylation process where the tert-butyl cation acts as the electrophile to alkylate 1,4-dimethoxybenzene.
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