Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Why is methanol chosen as the solvent for recrystallization? What would happen if the student uses dichloromethane instead?

Transcribed Image Text:In the current experiment, we will use a different electrophile (the tert-butyl cation) to alkylate 1,4-dimethoxybenzene. This is a Friedel-Crafts Alkylation reaction.
**Diagram Explanation:**
- **Left Side (Reactants):**
- The reactant is 1,4-dimethoxybenzene, which is a benzene ring with two methoxy groups (OCH₃) attached at the 1 and 4 positions. One methoxy group is depicted on the top right, and the other on the bottom left of the benzene ring.
- **Middle (Reaction Conditions):**
- Over the arrow, (CH₃)₃COH is shown, indicating that tert-butyl alcohol is used.
- Below the arrow, CH₃COOH/H₂SO₄ is noted, showing that acetic acid and sulfuric acid are used as the reaction conditions.
- **Right Side (Product):**
- The product is a benzene ring with methoxy groups (OCH₃) and two tert-butyl groups ((CH₃)₃C) attached at the 1 and 4 positions. The tert-butyl groups are depicted as (H₃C)₃C, placed above the top right and bottom right of the benzene ring.
The diagram illustrates the Friedel-Crafts Alkylation process where the tert-butyl cation acts as the electrophile to alkylate 1,4-dimethoxybenzene.
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