Why is fnot a function from R to R if a) f(x) = 1 f(x) is not a function because when x = is undefined is not real √2 0 -1 1 is false is defined has two distinct values f( is true 1/√2

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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**Why is \( f \) not a function from \( \mathbb{R} \) to \( \mathbb{R} \) if \( f(x) = \frac{1}{x} \)?**

\( f(x) \) is not a function because when \( x = \) [blank], \( f(x) \) [blank] [blank].

**Options:**

- is undefined
- 0
- is false
- is true
- is not real
- -1
- is defined
- \( \frac{1}{\sqrt{2}} \)
- \( \sqrt{2} \)
- 1
- has two distinct values

**Explanation:**

The function \( f(x) = \frac{1}{x} \) is not defined when \( x = 0 \) because division by zero is undefined in mathematics. Therefore, the correct answer is that \( f(x) \) is not a function when \( x = 0 \) because at this point, \( f(x) \) is undefined.
Transcribed Image Text:**Why is \( f \) not a function from \( \mathbb{R} \) to \( \mathbb{R} \) if \( f(x) = \frac{1}{x} \)?** \( f(x) \) is not a function because when \( x = \) [blank], \( f(x) \) [blank] [blank]. **Options:** - is undefined - 0 - is false - is true - is not real - -1 - is defined - \( \frac{1}{\sqrt{2}} \) - \( \sqrt{2} \) - 1 - has two distinct values **Explanation:** The function \( f(x) = \frac{1}{x} \) is not defined when \( x = 0 \) because division by zero is undefined in mathematics. Therefore, the correct answer is that \( f(x) \) is not a function when \( x = 0 \) because at this point, \( f(x) \) is undefined.
### Exploring the Function \( f(x) = \sqrt{x} \)

#### Question:
b) Is \( f(x) = \sqrt{x} \) a function?

#### Explanation:
The function \( f(x) = \sqrt{x} \) is described as not a function because when \( x \) is less than 0, \( f(x) \) is undefined. 

#### Interactive Elements:
- Options to complete the statement: 
  - \( x \)
  - \(\sqrt{0}\)
  - is false
  - \( = 0.1 \)
  - is defined
  - is true
  - \( f(x) \)
  - \( = 0 \)
  - \( < 0 \)
  - is undefined
  - \( f(0) \)
  - \( > 0 \)

#### Conclusion:
For \( f(x) = \sqrt{x} \), \( f(x) \) is undefined for \( x < 0 \), as the square root of a negative number is not defined within the set of real numbers. Hence, we confirm that \( f(x) \) can only be considered a function for \( x \geq 0 \).
Transcribed Image Text:### Exploring the Function \( f(x) = \sqrt{x} \) #### Question: b) Is \( f(x) = \sqrt{x} \) a function? #### Explanation: The function \( f(x) = \sqrt{x} \) is described as not a function because when \( x \) is less than 0, \( f(x) \) is undefined. #### Interactive Elements: - Options to complete the statement: - \( x \) - \(\sqrt{0}\) - is false - \( = 0.1 \) - is defined - is true - \( f(x) \) - \( = 0 \) - \( < 0 \) - is undefined - \( f(0) \) - \( > 0 \) #### Conclusion: For \( f(x) = \sqrt{x} \), \( f(x) \) is undefined for \( x < 0 \), as the square root of a negative number is not defined within the set of real numbers. Hence, we confirm that \( f(x) \) can only be considered a function for \( x \geq 0 \).
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