Why does the final product has the opposite configuration compared to the reactant? Shouldn’t it form OMs first, then OMs gets substituted by Cl- via Sn2 (the 1st inversion of configuration) then the Cl- gets substituted by OCH3- (the 2nd inversion of configuration? To my understanding 2 inversions = same configuration
Why does the final product has the opposite configuration compared to the reactant? Shouldn’t it form OMs first, then OMs gets substituted by Cl- via Sn2 (the 1st inversion of configuration) then the Cl- gets substituted by OCH3- (the 2nd inversion of configuration? To my understanding 2 inversions = same configuration
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Why does the final product has the opposite configuration compared to the reactant? Shouldn’t it form OMs first, then OMs gets substituted by Cl- via Sn2 (the 1st inversion of configuration) then the Cl- gets substituted by OCH3- (the 2nd inversion of configuration? To my understanding 2 inversions = same configuration

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