Why does the final product has the opposite configuration compared to the reactant? Shouldn’t it form OMs first, then OMs gets substituted by Cl- via Sn2 (the 1st inversion of configuration) then the Cl- gets substituted by OCH3- (the 2nd inversion of configuration? To my understanding 2 inversions = same configuration
Why does the final product has the opposite configuration compared to the reactant? Shouldn’t it form OMs first, then OMs gets substituted by Cl- via Sn2 (the 1st inversion of configuration) then the Cl- gets substituted by OCH3- (the 2nd inversion of configuration? To my understanding 2 inversions = same configuration
Organic Chemistry: A Guided Inquiry
2nd Edition
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Andrei Straumanis
Chapter14: Elimination
Section: Chapter Questions
Problem 22E
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Why does the final product has the opposite configuration compared to the reactant? Shouldn’t it form OMs first, then OMs gets substituted by Cl- via Sn2 (the 1st inversion of configuration) then the Cl- gets substituted by OCH3- (the 2nd inversion of configuration? To my understanding 2 inversions = same configuration
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