a 100N block lies on a frictionless surface. A force of 50N was applied horizontally on the block moving it 5m. find the work done by the applied force and the done by the weight of the block
a 100N block lies on a frictionless surface. A force of 50N was applied horizontally on the block moving it 5m. find the work done by the applied force and the done by the weight of the block
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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a 100N block lies on a frictionless surface. A force of 50N was applied horizontally on the block moving it 5m. find the work done by the applied force and the done by the weight of the block
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why 0(zero) at work done by the height of the block
![solution :-
The given situation is as follows
E = 50 N 2
Applied
farce.
:. The work
W₂
weight
F₂.dn'
& work done
is
done
7 dm² = 5m x
= 100N = 7₁ (Bay)
=
F
= 100 (-ŷ) N
applied force Fis
50 N X
5m x
= 50x5 N.m ‚Â
= 50X5 N.M
⇒ W₂ = 250 N.m = 250 J.
one by the weight force Fr of the bbck
W₁
F.dr
។ Lie
=
[4XX=1]
100N (-1). 5m x
=-100x5 (4.x) N.m
W₁ = 0
[+9₁8=0]](https://content.bartleby.com/qna-images/question/cf01c187-6139-4d96-a047-c30a7c0fa772/4233f4b5-bc11-40d0-9298-6623e3e31164/xgs088_processed.jpeg)
Transcribed Image Text:solution :-
The given situation is as follows
E = 50 N 2
Applied
farce.
:. The work
W₂
weight
F₂.dn'
& work done
is
done
7 dm² = 5m x
= 100N = 7₁ (Bay)
=
F
= 100 (-ŷ) N
applied force Fis
50 N X
5m x
= 50x5 N.m ‚Â
= 50X5 N.M
⇒ W₂ = 250 N.m = 250 J.
one by the weight force Fr of the bbck
W₁
F.dr
។ Lie
=
[4XX=1]
100N (-1). 5m x
=-100x5 (4.x) N.m
W₁ = 0
[+9₁8=0]
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