who use their own cups when they purchase a coffee beverage, and the proportion of customers who use their own cups when they purchase an espresso beverage. Customers using their own cups get a 5% discount, which is displayed on the receipt. The owner randomly selects 50 receipts from all coffee purchases and 50 receipts from all espresso purchases. For coffee purchases, 24 receipts showed that the customer used their own cup. For espresso purchases, 18 receipts showed that the customer used their own cup. Assuming the conditions for inference have been met, what is the 99% confidence interval for the difference in proportion of customers who use their own cups? Find the z-table here. O (0.48 - 0.36) ±2.58 0.48(1– 0.48) , 0.36(1-0.36) 50 50 O (0.48 - 0.36)±2.33, 0.48(1–0.48) 50 0.36(1-0.36) 50 O (0.52 - 0.64) ±2.58 0.52(1-0.52), 0.64(1–0.64) 100 100 0.52(1-0.52), 0.64(1–0.64) 100 (0.52 - 0.64) ±2.33, 100

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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The owner of a popular coffee shop wants to determine if there is a difference between the proportion of customers
who use their own cups when they purchase a coffee beverage, and the proportion of customers who use their own
cups when they purchase an espresso beverage. Customers using their own cups get a 5% discount, which is
displayed on the receipt. The owner randomly selects 50 receipts from all coffee purchases and 50 receipts from all
espresso purchases. For coffee purchases, 24 receipts showed that the customer used their own cup. For espresso
purchases, 18 receipts showed that the customer used their own cup. Assuming the conditions for inference have
been met, what is the 99% confidence interval for the difference in proportion of customers who use their own cups?
Find the z-table here.
O (0.48 - 0.36) ±2.58/
0.48(1–0.48) , 0.36(1–0.36)
50
50
0.48(1-0.48) 0.36(1-0.36)
(0.48 - 0.36) ±2.33/
50
50
O (0.52 - 0.64)±2.58
0.52(1-0.52) 0.64(1-0.64)
+
100
100
0.52(1-0.52) , 0.64(1-0.64)
(0.52 - 0.64) ±2.33,
100
100
Transcribed Image Text:The owner of a popular coffee shop wants to determine if there is a difference between the proportion of customers who use their own cups when they purchase a coffee beverage, and the proportion of customers who use their own cups when they purchase an espresso beverage. Customers using their own cups get a 5% discount, which is displayed on the receipt. The owner randomly selects 50 receipts from all coffee purchases and 50 receipts from all espresso purchases. For coffee purchases, 24 receipts showed that the customer used their own cup. For espresso purchases, 18 receipts showed that the customer used their own cup. Assuming the conditions for inference have been met, what is the 99% confidence interval for the difference in proportion of customers who use their own cups? Find the z-table here. O (0.48 - 0.36) ±2.58/ 0.48(1–0.48) , 0.36(1–0.36) 50 50 0.48(1-0.48) 0.36(1-0.36) (0.48 - 0.36) ±2.33/ 50 50 O (0.52 - 0.64)±2.58 0.52(1-0.52) 0.64(1-0.64) + 100 100 0.52(1-0.52) , 0.64(1-0.64) (0.52 - 0.64) ±2.33, 100 100
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