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Which XXX would replace the missing statement in the following algorithm? It inserts newNode after curNode. List::InsertAfter(curNode, newNode) { if (head == null) { head = newNode tail = newNode XXX { tail-next = newNode newNode prev = tail tail = newNode else { sucNode = curNode--next newNode-next = sucNode newNode»prev = curNode curNode»next = newNode sucNode »prev = newNode } } else if (curNode tail) else if (curNode != head) else if (curNode == head) else if (sucNode == tail)

Which XXX would replace the missing statement in the following algorithm? It inserts newNode after curNode. List::InsertAfter(curNode, newNode) { if (head == null) { head = newNode tail = newNode XXX { tail-next = newNode newNode prev = tail tail = newNode else { sucNode = curNode--next newNode-next = sucNode newNode»prev = curNode curNode»next = newNode sucNode »prev = newNode } } else if (curNode tail) else if (curNode != head) else if (curNode == head) else if (sucNode == tail)

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Which XXX would replace the missing statement in the following algorithm? It inserts (newNode) after curNode . List::InsertAfter(curNode, newNode) { null) { if (head head = newNode =3= tail = newNode } XXX { tail»next = newNode newNode--prev newNode tail = tail } else { sucNode = curNode»next newNodenext = sucNode newNode--prev curNode»next curNode newNode sucNodeprev } } = newNode else if (curNode tail) else if (curNode != head) else if (curNode head) == else if (sucNode tail) ==
Transcribed Image Text:Which XXX would replace the missing statement in the following algorithm? It inserts (newNode) after curNode . List::InsertAfter(curNode, newNode) { null) { if (head head = newNode =3= tail = newNode } XXX { tail»next = newNode newNode--prev newNode tail = tail } else { sucNode = curNode»next newNodenext = sucNode newNode--prev curNode»next curNode newNode sucNodeprev } } = newNode else if (curNode tail) else if (curNode != head) else if (curNode head) == else if (sucNode tail) ==
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