Which would the cell potential be if you changed the concentrations to [Fe3*] = 0.60 [Hg²*) = 1.30 M [Hg22*] = 0.70 M [Fe2*] = 1.50 M Would the reaction become more spontaneous or less spontaneous under these new concentrations?

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Worked out the first two steps to the problem just need help with the last where it's asking what the cell potential be with the changes to concentration

 

Which would the cell potential be if you changed the concentrations to
[Fe3*] = 0.60 [Hg²*) = 1.30 M
[Hg22*] = 0.70 M
[Fe2*] = 1.50 M
Would the reaction become more spontaneous or less spontaneous under these new
concentrations?
Transcribed Image Text:Which would the cell potential be if you changed the concentrations to [Fe3*] = 0.60 [Hg²*) = 1.30 M [Hg22*] = 0.70 M [Fe2*] = 1.50 M Would the reaction become more spontaneous or less spontaneous under these new concentrations?
Expert Solution
Step 1

The Nernst equation is shown below:

Chemistry homework question answer, step 1, image 1

Where:

Ecell = cell potential

E0cell = standard cell potential

R = gas constant

T = temperature

F = Faraday's constant

Q = reaction quotient

 

Step 2

Given information:

Concentration of Fe3+ = 0.60 M

Concentration of Hg2+ = 1.30 M

Concentration of Hg22+ = 0.70 M

Concentration of Fe2+ = 1.50 M

E0cell = 0.15 V

Step 3

The cell reaction is shown below:

Chemistry homework question answer, step 3, image 1

 

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