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Which way of dispensing champagne, the traditional vertical method or a tilted beer-like pour, preserves more of the tiny gas bubbles that improve flavor and aroma? The following data was reported in an article. Temp (°C) Type of Pour n Mean (g/L) SD 18 Traditional 4 4.0 0.5 18 Slanted 4 3.7 0.3 12 Traditional 4 3.4 0.4 12 Slanted 4 2.0 0.2 Assume that the sampled distributions are normal. I A USE SALT (a) Carry out a test at significance level 0.01 to decide whether true average Co, loss at 18°C for the traditional pour differs from that for the slanted pour. (Use , for the traditional pour and , for the slanted pour.) State the relevant hypotheses. O Hg: M, - H2 > 0 H,: H - H2 = 0 O Hạ: M - 2 - o Hi M - H2 > 0 O Hg: H - H2 = 0 Hi - H2 <0 O Hg: M - H2 = 0 Hi H - H2 +0 O H: , - H, < 0 HH, - H, = 0 Calculate the test statistic and P-value. (Round your test statistic to one decimal place and your P-value to three decimal places.) P-value- State the conclusion in the problem context. O Reject Hg. The data suggest that the true average Co, loss at 18°C for the traditional pour differs from that for the slanted pour. O Fail to reject H. The data do not suggest that the true average co, loss at 18°C for the traditional pour differs from that for the slanted pour. O Reject Hg. The data do not suggest that the true average Co, loss at 18°C for the traditional pour differs from that for the slanted pour. O Fail to reject H. The data suggest that the true average Co, loss at 18°C for the traditional pour differs from that for the slanted pour. (b) Repeat the test of hypotheses suggested in (a) for the 12° temperature. Is the conclusion different from that for the 18° temperature? Note: The 12° result was reported in the popular media. (Use , for the traditional pour and H, for the slanted pour.) State the relevant hypotheses. O Hg: H - H2 < 0 O Ha: H - H2 - 0 H - H2 > 0

Which way of dispensing champagne, the traditional vertical method or a tilted beer-like pour, preserves more of the tiny gas bubbles that improve flavor and aroma? The following data was reported in an article. Temp (°C) Type of Pour n Mean (g/L) SD 18 Traditional 4 4.0 0.5 18 Slanted 4 3.7 0.3 12 Traditional 4 3.4 0.4 12 Slanted 4 2.0 0.2 Assume that the sampled distributions are normal. I A USE SALT (a) Carry out a test at significance level 0.01 to decide whether true average Co, loss at 18°C for the traditional pour differs from that for the slanted pour. (Use , for the traditional pour and , for the slanted pour.) State the relevant hypotheses. O Hg: M, - H2 > 0 H,: H - H2 = 0 O Hạ: M - 2 - o Hi M - H2 > 0 O Hg: H - H2 = 0 Hi - H2 <0 O Hg: M - H2 = 0 Hi H - H2 +0 O H: , - H, < 0 HH, - H, = 0 Calculate the test statistic and P-value. (Round your test statistic to one decimal place and your P-value to three decimal places.) P-value- State the conclusion in the problem context. O Reject Hg. The data suggest that the true average Co, loss at 18°C for the traditional pour differs from that for the slanted pour. O Fail to reject H. The data do not suggest that the true average co, loss at 18°C for the traditional pour differs from that for the slanted pour. O Reject Hg. The data do not suggest that the true average Co, loss at 18°C for the traditional pour differs from that for the slanted pour. O Fail to reject H. The data suggest that the true average Co, loss at 18°C for the traditional pour differs from that for the slanted pour. (b) Repeat the test of hypotheses suggested in (a) for the 12° temperature. Is the conclusion different from that for the 18° temperature? Note: The 12° result was reported in the popular media. (Use , for the traditional pour and H, for the slanted pour.) State the relevant hypotheses. O Hg: H - H2 < 0 O Ha: H - H2 - 0 H - H2 > 0

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Which way of dispensing champagne, the traditional vertical method or a tilted beer-like pour, preserves more of the tiny gas bubbles that improve flavor and aroma? The following data was reported in an article. Temp (°C) TYpe of Pour n Mean (g/L) SD 18 Traditional 4.0 0.5 18 Slanted 4 3.7 0.3 12 Traditional 4 3.4 0.4 12 Slanted 4 2.0 0.2 Assume that the sampled distributions are normal. A USE SALT (a) Carry out a test at significance level 0.01 to decide whether true average Co, loss at 18°C for the traditional pour differs from that for the slanted pour. (Use u, for the traditional pour and , for the slanted pour.) State the relevant hypotheses. O Ha: H, - H, >0 H H - H2 = o O Hạ: H, - H2 - o H: H - H2 > 0 O H: H, - H2 = 0 H: H1 - H2 <0 O Hạ: H - H2 = 0 O H: H, - 4, < o H - "2 = 0 Calculate the test statistic and P-value. (Round your test statistic to one decimal place and your P-value to three decimal places.) t = P-value- State the conclusion in the problem context. O Reject H. The data suggest that the true average co, loss at 18°C for the traditional pour differs from that for the slanted pour. O Fail to reject H. The data do not suggest that the true average Co, loss at 18°C for the traditional pour differs from that for the slanted pour. O Reject H. The data do not suggest that the true average co, loss at 18°C for the traditional pour differs from that for the slanted pour. O Fail to reject H. The data suggest that the true average Co, loss at 18°C for the traditional pour differs from that for the slanted pour. (b) Repeat the test of hypotheses suggested in (a) for the 12° temperature. Is the conclusion different from that for the 18° temperature? Note: The 12° result was reported in the popular media. (Use 4, for the traditional pour and H, for the slanted pour.) State the relevant hypotheses. O Hạ: M. - H2 <0 H H - H2 =0 O Hạ: H, - H2 - 0 H: H1 - #2 > 0
Transcribed Image Text:Which way of dispensing champagne, the traditional vertical method or a tilted beer-like pour, preserves more of the tiny gas bubbles that improve flavor and aroma? The following data was reported in an article. Temp (°C) TYpe of Pour n Mean (g/L) SD 18 Traditional 4.0 0.5 18 Slanted 4 3.7 0.3 12 Traditional 4 3.4 0.4 12 Slanted 4 2.0 0.2 Assume that the sampled distributions are normal. A USE SALT (a) Carry out a test at significance level 0.01 to decide whether true average Co, loss at 18°C for the traditional pour differs from that for the slanted pour. (Use u, for the traditional pour and , for the slanted pour.) State the relevant hypotheses. O Ha: H, - H, >0 H H - H2 = o O Hạ: H, - H2 - o H: H - H2 > 0 O H: H, - H2 = 0 H: H1 - H2 <0 O Hạ: H - H2 = 0 O H: H, - 4, < o H - "2 = 0 Calculate the test statistic and P-value. (Round your test statistic to one decimal place and your P-value to three decimal places.) t = P-value- State the conclusion in the problem context. O Reject H. The data suggest that the true average co, loss at 18°C for the traditional pour differs from that for the slanted pour. O Fail to reject H. The data do not suggest that the true average Co, loss at 18°C for the traditional pour differs from that for the slanted pour. O Reject H. The data do not suggest that the true average co, loss at 18°C for the traditional pour differs from that for the slanted pour. O Fail to reject H. The data suggest that the true average Co, loss at 18°C for the traditional pour differs from that for the slanted pour. (b) Repeat the test of hypotheses suggested in (a) for the 12° temperature. Is the conclusion different from that for the 18° temperature? Note: The 12° result was reported in the popular media. (Use 4, for the traditional pour and H, for the slanted pour.) State the relevant hypotheses. O Hạ: M. - H2 <0 H H - H2 =0 O Hạ: H, - H2 - 0 H: H1 - #2 > 0
(b) Repeat the test of hypotheses suggested in (a) for the 12° temperature. Is the conclusion different from that for the 18° temperature? Note: The 12° result was reported in the popular media. (Use u, for the traditional pour and , for the slanted pour.) State the relevant hypotheses. O Ha: H - H2 <0 H: H - H2 = o O Hg: H - H2 -0 H: H, - H2 >0 O Hạ: H - 42 - o H.: H1 - 2 +0 O Hg: H - 42 = 0 H: " - 2 < 0 O H: H - H2 > 0 H: "- H, = 0 Calculate the test statistic and P-value. (Round your test statistic to one decimal place and your P-value three decimal places.) P-value = State the conclusion in the problem context. O Fail to reject H. The data suggest that the true average Co, loss at 12°C for the traditional pour differs from that for the slanted pour. O Reject H. The data suggest that the true average co, loss at 12°C for the traditional pour differs from that for the slanted pour. O Reject Hg. The data do not suggest that the true average Co, loss at 12°C for the traditional pour differs from that for the slanted pour. O Fail to reject Hp. The data do not suggest that the true average co, loss at 12°C for the traditional pour differs from that for the slanted pour.
Transcribed Image Text:(b) Repeat the test of hypotheses suggested in (a) for the 12° temperature. Is the conclusion different from that for the 18° temperature? Note: The 12° result was reported in the popular media. (Use u, for the traditional pour and , for the slanted pour.) State the relevant hypotheses. O Ha: H - H2 <0 H: H - H2 = o O Hg: H - H2 -0 H: H, - H2 >0 O Hạ: H - 42 - o H.: H1 - 2 +0 O Hg: H - 42 = 0 H: " - 2 < 0 O H: H - H2 > 0 H: "- H, = 0 Calculate the test statistic and P-value. (Round your test statistic to one decimal place and your P-value three decimal places.) P-value = State the conclusion in the problem context. O Fail to reject H. The data suggest that the true average Co, loss at 12°C for the traditional pour differs from that for the slanted pour. O Reject H. The data suggest that the true average co, loss at 12°C for the traditional pour differs from that for the slanted pour. O Reject Hg. The data do not suggest that the true average Co, loss at 12°C for the traditional pour differs from that for the slanted pour. O Fail to reject Hp. The data do not suggest that the true average co, loss at 12°C for the traditional pour differs from that for the slanted pour.
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