Which type of discontinuity does the function exhibit at x = 3? %3D (-x2 + 1, -1 sx<0 2х, f(x) = 0

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Which type of discontinuity does the function exhibit at x = 3?
-x2 + 1, -1 sx<0
2x,
f(x) ={ -4,
0<x<1
x = 1
%3D
-2x + 4
1<x<3
2,
3<x<5
-6 -5 -4 -3 -2 -1.
1 2 3
5 6
4
-2
-3+
O Removable discontinuity
O Jump discontinuity
O Infinite discontinuity
O None of these because the function is continuous at x = 3
5.
Transcribed Image Text:Which type of discontinuity does the function exhibit at x = 3? -x2 + 1, -1 sx<0 2x, f(x) ={ -4, 0<x<1 x = 1 %3D -2x + 4 1<x<3 2, 3<x<5 -6 -5 -4 -3 -2 -1. 1 2 3 5 6 4 -2 -3+ O Removable discontinuity O Jump discontinuity O Infinite discontinuity O None of these because the function is continuous at x = 3 5.
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