Which two compounds ionize with loss of bromide ion to form the same carbocation? CH3 CH3 CH3 CH2 H3C =CH2 H3C H3C CH3 H3C Br Br Br Br A C O A and B O A and D O B and C O C and D

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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**Question:**
Which two compounds ionize with loss of bromide ion to form the same carbocation?

**Image Description:**
The image displays the structural formulas of four organic compounds labeled A, B, C, and D. Each of these compounds contains a bromine (Br) atom.

- Compound A: CH3-CH=CH-CH2-Br
- Compound B: CH3-C(Br)-CH=CH-CH3
- Compound C: CH3-CH=CH-CH2-CH2-Br
- Compound D: (CH3)2C=CH-CH2-Br

**Options:**
- O A and B
- O A and D
- O B and C
- O C and D

*Note for the Educator:*
The question requires students to identify which two compounds will lose a bromide ion, resulting in the same carbocation structure after ionization. Understanding the stability and the structure of carbocations is essential to solve this question.

**Explanation and Solution:**
To determine which compounds form the same carbocation upon losing a bromide ion, students need to draw out the potential carbocations and compare their structures.
Transcribed Image Text:**Question:** Which two compounds ionize with loss of bromide ion to form the same carbocation? **Image Description:** The image displays the structural formulas of four organic compounds labeled A, B, C, and D. Each of these compounds contains a bromine (Br) atom. - Compound A: CH3-CH=CH-CH2-Br - Compound B: CH3-C(Br)-CH=CH-CH3 - Compound C: CH3-CH=CH-CH2-CH2-Br - Compound D: (CH3)2C=CH-CH2-Br **Options:** - O A and B - O A and D - O B and C - O C and D *Note for the Educator:* The question requires students to identify which two compounds will lose a bromide ion, resulting in the same carbocation structure after ionization. Understanding the stability and the structure of carbocations is essential to solve this question. **Explanation and Solution:** To determine which compounds form the same carbocation upon losing a bromide ion, students need to draw out the potential carbocations and compare their structures.
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