Which trig ratio would you use to solve for the missing angle measures

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Which trig ratio would you use to solve for the missing angle measures

**Trigonometry Problem - Solving for Angles**

In this question, we will explore how to solve for a missing angle in a right triangle using trigonometric ratios.

**Question 7/10**

**Part A**

Given a right triangle:

- The side opposite the angle \( x \) has a length of 3 units.
- The hypotenuse has a length of 25 units.

Which trigonometric ratio would you use to solve for the missing angle measure?

Options:
A) \( \cos^{-1} \left( \frac{3}{25} \right) \)

B) \( \cos^{-1} \left( \frac{25}{3} \right) \)

C) \( \sin^{-1} \left( \frac{3}{25} \right) \)

D) \( \sin^{-1} \left( \frac{25}{3} \right) \)

**Part B**

Find the measure of angle \( x \). Round the answer to the nearest whole number.

---

**Explanation for Diagrams and Graphs:**

The diagram provided illustrates a right triangle with one angle labeled as \( x^\circ \):

- One leg of the triangle (adjacent to the right angle) measures 3 units.
- The hypotenuse of the triangle measures 25 units.
  
To solve for the angle \( x \), you would use the sine trigonometric function, \( \sin(x) \), because it involves the ratio of the length of the opposite side to the hypotenuse:

\[ \sin(x) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{3}{25} \]

Thus, you would use the inverse sine function to find angle \( x \):

\[ x = \sin^{-1} \left( \frac{3}{25} \right) \]

After solving for \( x \) using a calculator:

\[ x \approx \sin^{-1} \left( 0.12 \right) \approx 7^\circ \]

Therefore, the correct answers are:
  
**Part A:** Answer C) \( \sin^{-1} \left( \frac{3}{25} \right) \)

**Part B:** The measure of angle \( x \) is approximately 7 degrees.
Transcribed Image Text:**Trigonometry Problem - Solving for Angles** In this question, we will explore how to solve for a missing angle in a right triangle using trigonometric ratios. **Question 7/10** **Part A** Given a right triangle: - The side opposite the angle \( x \) has a length of 3 units. - The hypotenuse has a length of 25 units. Which trigonometric ratio would you use to solve for the missing angle measure? Options: A) \( \cos^{-1} \left( \frac{3}{25} \right) \) B) \( \cos^{-1} \left( \frac{25}{3} \right) \) C) \( \sin^{-1} \left( \frac{3}{25} \right) \) D) \( \sin^{-1} \left( \frac{25}{3} \right) \) **Part B** Find the measure of angle \( x \). Round the answer to the nearest whole number. --- **Explanation for Diagrams and Graphs:** The diagram provided illustrates a right triangle with one angle labeled as \( x^\circ \): - One leg of the triangle (adjacent to the right angle) measures 3 units. - The hypotenuse of the triangle measures 25 units. To solve for the angle \( x \), you would use the sine trigonometric function, \( \sin(x) \), because it involves the ratio of the length of the opposite side to the hypotenuse: \[ \sin(x) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{3}{25} \] Thus, you would use the inverse sine function to find angle \( x \): \[ x = \sin^{-1} \left( \frac{3}{25} \right) \] After solving for \( x \) using a calculator: \[ x \approx \sin^{-1} \left( 0.12 \right) \approx 7^\circ \] Therefore, the correct answers are: **Part A:** Answer C) \( \sin^{-1} \left( \frac{3}{25} \right) \) **Part B:** The measure of angle \( x \) is approximately 7 degrees.
**Question 7/10**

**Diagram:**
- A right-angled triangle is shown. The side opposite the right angle (hypotenuse) is labeled as 25.
- The side adjacent to angle \( x^\circ \) is labeled as 3.
- Another side is unlabeled.

### Part A

**Which trig ratio would you use to solve for the missing angle measure?**

A) \(\cos^{-1}\left(\dfrac{3}{25}\right)\)

B) \(\cos^{-1}\left(\dfrac{25}{3}\right)\)

C) \(\sin^{-1}\left(\dfrac{3}{25}\right)\)

D) \(\sin^{-1}\left(\dfrac{25}{3}\right)\)

### Part B

**Find the measure of angle \( x \). Round answer to nearest whole number.**

(Answer box provided)
Transcribed Image Text:**Question 7/10** **Diagram:** - A right-angled triangle is shown. The side opposite the right angle (hypotenuse) is labeled as 25. - The side adjacent to angle \( x^\circ \) is labeled as 3. - Another side is unlabeled. ### Part A **Which trig ratio would you use to solve for the missing angle measure?** A) \(\cos^{-1}\left(\dfrac{3}{25}\right)\) B) \(\cos^{-1}\left(\dfrac{25}{3}\right)\) C) \(\sin^{-1}\left(\dfrac{3}{25}\right)\) D) \(\sin^{-1}\left(\dfrac{25}{3}\right)\) ### Part B **Find the measure of angle \( x \). Round answer to nearest whole number.** (Answer box provided)
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