Which structures are the most important and less important contributors to the resonance hybrid for the azide anion, N,. :N-NEN : :NEN-N? N=N=N A в -N=N. *N=N=N* D E Identify the most important contributor(s): Identify the less important contributor(s): A A В В C C D D E E
Which structures are the most important and less important contributors to the resonance hybrid for the azide anion, N,. :N-NEN : :NEN-N? N=N=N A в -N=N. *N=N=N* D E Identify the most important contributor(s): Identify the less important contributor(s): A A В В C C D D E E
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Which structures are the most important and less important contributors to the resonance hybrid for the azide anion, N, .
:N-NEN :
:NEN-N?
N=N=N
A
в
-N=N.
*N=N=N*
D
E
Identify the most important contributor(s):
Identify the less important contributor(s):
A
A
В
В
C
C
D
D
E
E
Expert Solution
Step 1
There are two ways to do it. Hera i've done it in by following method.
Calculate V , the number of valence electrons we actually have available
N3- = (3N atoms) +( 1 e- because of -ve charge)
=(3*5valence electrons on each N) + (1)
= 16 valence elctrons
So,total number of valence electrons = 16 valence electrons
Calculate P , the number of π electrons there must be in the molecule:
No. Of pi electrons= 6n +2 - V
n = number of atoms other than H= 3N in this case
v = Valence electrons=16 e-
putting values,
No. Of pi electrons= (6×3) +2-16 = 20-16= 4pi electrons
So there are either two double bonds or one triple bond.
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