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Which structures are the most important and less important contributors to the resonance hybrid for the azide anion, N,. :N-NEN : :NEN-N? N=N=N A в -N=N. *N=N=N* D E Identify the most important contributor(s): Identify the less important contributor(s): A A В В C C D D E E

Which structures are the most important and less important contributors to the resonance hybrid for the azide anion, N,. :N-NEN : :NEN-N? N=N=N A в -N=N. *N=N=N* D E Identify the most important contributor(s): Identify the less important contributor(s): A A В В C C D D E E

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Which structures are the most important and less important contributors to the resonance hybrid for the azide anion, N, . :N-NEN : :NEN-N? N=N=N A в -N=N. *N=N=N* D E Identify the most important contributor(s): Identify the less important contributor(s): A A В В C C D D E E
Transcribed Image Text:Which structures are the most important and less important contributors to the resonance hybrid for the azide anion, N, . :N-NEN : :NEN-N? N=N=N A в -N=N. *N=N=N* D E Identify the most important contributor(s): Identify the less important contributor(s): A A В В C C D D E E
Expert Solution
Step 1

There are two ways to do it. Hera i've done it in by following method.

Calculate V , the number of valence electrons we actually have available

N3- = (3N atoms) +( 1 e- because of -ve charge)

        =(3*5valence electrons on each N) + (1)

        = 16 valence elctrons

So,total number of valence electrons = 16 valence electrons

Calculate  P , the number of π electrons there must be in the molecule:

No. Of pi electrons= 6n +2 - V

n = number of atoms other than H= 3N in this case

v = Valence electrons=16 e-

putting values,

No. Of pi electrons= (6×3) +2-16 = 20-16= 4pi electrons

So there are either two double bonds or one triple bond.

 

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