Which statement is true? O A. The function f(1) tan(r) is an odd function because f(-r) -f(x). %3D В. The function f(r) tan(r) is an even function because its graph is symmetric about the origin. OC. The function f(x) = tan(x) is an odd function because its graph is symmetric about the y-axis. O D. The function f(x) = tan(x) is an even function because f(-x) = f(x).

Algebra and Trigonometry (6th Edition)
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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### Which statement is true?

**A.** The function \( f(x) = \tan(x) \) is an odd function because \( f(-x) = -f(x) \).

**B.** The function \( f(x) = \tan(x) \) is an even function because its graph is symmetric about the origin.

**C.** The function \( f(x) = \tan(x) \) is an odd function because its graph is symmetric about the \( y \)-axis.

**D.** The function \( f(x) = \tan(x) \) is an even function because \( f(-x) = f(x) \).

This is a multiple-choice question asking which of the given statements about the function \( f(x) = \tan(x) \) is true. The statements refer to the properties of the function regarding its symmetry and whether it is classified as an odd or even function.

- **Odd Function:** A function \( f(x) \) is odd if \( f(-x) = -f(x) \). This means its graph is symmetric with respect to the origin.
- **Even Function:** A function \( f(x) \) is even if \( f(-x) = f(x) \). This means its graph is symmetric with respect to the \( y \)-axis.

In this case, option **A** is correct because the tangent function \( f(x) = \tan(x) \) is an odd function, satisfying the condition \( f(-x) = -f(x) \). Options B, C, and D are incorrect because they wrongly classify the function as even or provide incorrect reasons for its classification.
Transcribed Image Text:### Which statement is true? **A.** The function \( f(x) = \tan(x) \) is an odd function because \( f(-x) = -f(x) \). **B.** The function \( f(x) = \tan(x) \) is an even function because its graph is symmetric about the origin. **C.** The function \( f(x) = \tan(x) \) is an odd function because its graph is symmetric about the \( y \)-axis. **D.** The function \( f(x) = \tan(x) \) is an even function because \( f(-x) = f(x) \). This is a multiple-choice question asking which of the given statements about the function \( f(x) = \tan(x) \) is true. The statements refer to the properties of the function regarding its symmetry and whether it is classified as an odd or even function. - **Odd Function:** A function \( f(x) \) is odd if \( f(-x) = -f(x) \). This means its graph is symmetric with respect to the origin. - **Even Function:** A function \( f(x) \) is even if \( f(-x) = f(x) \). This means its graph is symmetric with respect to the \( y \)-axis. In this case, option **A** is correct because the tangent function \( f(x) = \tan(x) \) is an odd function, satisfying the condition \( f(-x) = -f(x) \). Options B, C, and D are incorrect because they wrongly classify the function as even or provide incorrect reasons for its classification.
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