Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question

A cyclohexane ring with a double bond between carbons 1 and 2, and a methyl group (CH₃) attached to carbon 1.
**B.**

A cyclohexane ring with a double bond between carbons 2 and 3, and a methyl group (CH₃) attached to carbon 3.
**C.**

A cyclohexane ring with a double bond between carbons 1 and 6, and a methyl group (CH₃) attached to carbon 1.
**D.**

A cyclohexane ring with a hydroxyl group (OH) attached to carbon 1 and a methyl group (CH₃) attached to carbon 1.
#### Explanation:
The reaction involves the use of mCPBA (meta-chloroperoxybenzoic acid) followed by hydrolysis (H₃O⁺). The chosen starting material must undergo an epoxidation with mCPBA, which typically adds an oxygen atom across the double bond to form an epoxide. This epoxide is then hydrolyzed by H₃O⁺ to produce two hydroxyl groups.
**Step-by-Step Solution:**
1. **mCPBA Epoxidation:**
- Adds an oxygen atom to both carbons of the double bond, forming an epoxide ring.
2. **H₃O⁺ Hydrolysis:**
- The epoxide ring is opened by hydrolysis to form trans-diols (two hydroxyl groups on adjacent carbons).
To achieve the given trans-diols configuration, we should consider the formation and opening of the epoxide ring, and structure and position of the substituents in the given options.
By examining the given options:
**Option A** involves a double bond conducive to epoxide formation. When hydrolyzed, it could yield the product shown with trans-diols.
**Correct Answer: A**](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe4d0ca9f-229e-40d6-ac53-f10954775736%2Fd818ef31-d467-445a-9f89-8205364a26fa%2F6hgfy7i_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Reaction Mechanism and Product Determination
**Question:** Which starting material yields this product?
#### Reaction:
1) mCPBA
2) H₃O⁺
#### Product:
The product shown is a molecule with two hydroxyl groups (OH) attached to a cyclohexane ring.
#### Options:
**A.**

A cyclohexane ring with a double bond between carbons 1 and 2, and a methyl group (CH₃) attached to carbon 1.
**B.**

A cyclohexane ring with a double bond between carbons 2 and 3, and a methyl group (CH₃) attached to carbon 3.
**C.**

A cyclohexane ring with a double bond between carbons 1 and 6, and a methyl group (CH₃) attached to carbon 1.
**D.**

A cyclohexane ring with a hydroxyl group (OH) attached to carbon 1 and a methyl group (CH₃) attached to carbon 1.
#### Explanation:
The reaction involves the use of mCPBA (meta-chloroperoxybenzoic acid) followed by hydrolysis (H₃O⁺). The chosen starting material must undergo an epoxidation with mCPBA, which typically adds an oxygen atom across the double bond to form an epoxide. This epoxide is then hydrolyzed by H₃O⁺ to produce two hydroxyl groups.
**Step-by-Step Solution:**
1. **mCPBA Epoxidation:**
- Adds an oxygen atom to both carbons of the double bond, forming an epoxide ring.
2. **H₃O⁺ Hydrolysis:**
- The epoxide ring is opened by hydrolysis to form trans-diols (two hydroxyl groups on adjacent carbons).
To achieve the given trans-diols configuration, we should consider the formation and opening of the epoxide ring, and structure and position of the substituents in the given options.
By examining the given options:
**Option A** involves a double bond conducive to epoxide formation. When hydrolyzed, it could yield the product shown with trans-diols.
**Correct Answer: A**
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