Which starting material yields this product? 1) тСРВА 2) H3O* OH ОН А. В. С. OH D.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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### Reaction Mechanism and Product Determination

**Question:** Which starting material yields this product?

#### Reaction:
1) mCPBA
2) H₃O⁺

#### Product:
The product shown is a molecule with two hydroxyl groups (OH) attached to a cyclohexane ring.

#### Options:
**A.**  
![A.](#)  
A cyclohexane ring with a double bond between carbons 1 and 2, and a methyl group (CH₃) attached to carbon 1.

**B.**  
![B.](#)  
A cyclohexane ring with a double bond between carbons 2 and 3, and a methyl group (CH₃) attached to carbon 3.

**C.**  
![C.](#)  
A cyclohexane ring with a double bond between carbons 1 and 6, and a methyl group (CH₃) attached to carbon 1.

**D.**  
![D.](#)  
A cyclohexane ring with a hydroxyl group (OH) attached to carbon 1 and a methyl group (CH₃) attached to carbon 1.

#### Explanation:
The reaction involves the use of mCPBA (meta-chloroperoxybenzoic acid) followed by hydrolysis (H₃O⁺). The chosen starting material must undergo an epoxidation with mCPBA, which typically adds an oxygen atom across the double bond to form an epoxide. This epoxide is then hydrolyzed by H₃O⁺ to produce two hydroxyl groups.

**Step-by-Step Solution:**

1. **mCPBA Epoxidation:**
   - Adds an oxygen atom to both carbons of the double bond, forming an epoxide ring.

2. **H₃O⁺ Hydrolysis:**
   - The epoxide ring is opened by hydrolysis to form trans-diols (two hydroxyl groups on adjacent carbons).

To achieve the given trans-diols configuration, we should consider the formation and opening of the epoxide ring, and structure and position of the substituents in the given options.

By examining the given options:

**Option A** involves a double bond conducive to epoxide formation. When hydrolyzed, it could yield the product shown with trans-diols.

**Correct Answer: A**
Transcribed Image Text:### Reaction Mechanism and Product Determination **Question:** Which starting material yields this product? #### Reaction: 1) mCPBA 2) H₃O⁺ #### Product: The product shown is a molecule with two hydroxyl groups (OH) attached to a cyclohexane ring. #### Options: **A.** ![A.](#) A cyclohexane ring with a double bond between carbons 1 and 2, and a methyl group (CH₃) attached to carbon 1. **B.** ![B.](#) A cyclohexane ring with a double bond between carbons 2 and 3, and a methyl group (CH₃) attached to carbon 3. **C.** ![C.](#) A cyclohexane ring with a double bond between carbons 1 and 6, and a methyl group (CH₃) attached to carbon 1. **D.** ![D.](#) A cyclohexane ring with a hydroxyl group (OH) attached to carbon 1 and a methyl group (CH₃) attached to carbon 1. #### Explanation: The reaction involves the use of mCPBA (meta-chloroperoxybenzoic acid) followed by hydrolysis (H₃O⁺). The chosen starting material must undergo an epoxidation with mCPBA, which typically adds an oxygen atom across the double bond to form an epoxide. This epoxide is then hydrolyzed by H₃O⁺ to produce two hydroxyl groups. **Step-by-Step Solution:** 1. **mCPBA Epoxidation:** - Adds an oxygen atom to both carbons of the double bond, forming an epoxide ring. 2. **H₃O⁺ Hydrolysis:** - The epoxide ring is opened by hydrolysis to form trans-diols (two hydroxyl groups on adjacent carbons). To achieve the given trans-diols configuration, we should consider the formation and opening of the epoxide ring, and structure and position of the substituents in the given options. By examining the given options: **Option A** involves a double bond conducive to epoxide formation. When hydrolyzed, it could yield the product shown with trans-diols. **Correct Answer: A**
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