Which SQL statement lists the number of employees in each department? SELECT COUNT(EmployeeID), Department FROM Employees WHERE Department; SELECT COUNT(EmployeeID), Department FROM Employees GROUP BY Department; SELECT MAX(EmployeeID), Department FROM Employees GROUP BY Department; SELECT Employee ID, Department FROM Employees WHERE COUNT (EmployeeID) GROUP BY Department;

Which SQL statement lists the number of employees in each department? SELECT COUNT(EmployeeID), Department FROM Employees WHERE Department; SELECT COUNT(EmployeeID), Department FROM Employees GROUP BY Department; SELECT MAX(EmployeeID), Department FROM Employees GROUP BY Department; SELECT Employee ID, Department FROM Employees WHERE COUNT (EmployeeID) GROUP BY Department;

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

Based on the following SQL statement: SELECT acct_id, balance FROM Account WHERE balance < 0 AND acct_type = 'Checking' Which if the following is False? Query is retrieving data from the acct_id and balance columns Query is retrieving data from the Account table Query is retrieving all checking accounts with negative balance Query returns all columns from every row in the Account table
With SQL code, find the name of each employee with a manager along with their manager's name (use cartesian product and rename) Employee table: create table employee( ID varchar(6) not null,person_name varchar(10),street varchar(10),city varchar(10),primary key (ID)); Manages table: create table manages(ID varchar(6) not null,manager_id varchar(6),primary key (ID),foreign key (ID) references employee,foreign key (manager_id) references employee);
Write the SQL code to list the customer ID, first name, last name, street, city, state, zip and the count of times that the customer has rented a car since October 1, 2018. Use the mm/dd/yy format for the date. Place the list in descending order by the count.
Using SQL determine salary is above 4000 and job_id starts with a letter “S” In addition, when grouping the above selected employees by department, we only show the department which has more than 5 employees or the minimal salary greater than 5000, and order the result by the average salary.
Examine the EMPLOYEES table and the given SQL statement: EID Name Dept Salary 1001 Aminah IT 600 1002 Zainab Admin 400 1003 Tafal IT SELECT Name, Dept, Salary FROM employees WHERE name LIKE'_a%' AND salary IS NULL; Which of the following will be the output after executing the statément? a. Name Dept Salary Tafal IT b. Name Dept Salary Aminah IT 600 Zainab Admin 400 Name Dept Salary Zainab Admin 400 Name Dept Salary Aminah IT 600 DELL
question 11 please use the picture below to answer the following question Write a SQL statement to change the value of the column Invoice_Date (new_invoice table) to today's date for Customer ID 10.
Write all the sql code (including create, insert and select)
Write SQL queries for the following. Display details of those patients whose age is either 25 or 36 or 29 without using comparison operator. Display first name and last name of those doctors whose salary is less than or equal to 77,000 and greater than or equal to 50,000 using between operator. Display details of those doctors who neither belong to Isb nor Rwp nor Multan without using in and like operator. Display full name of doctors whose first name is other than Tania. Display first name of doctors whose first name contains any of vowels (a,e,i,o,u). Display names of those patients whose name’s second letter is neither ‘a’ nor ‘d’ Display details of those male patients whose age is 25 or 36. Display details of those patients whose name contains less than 5 characters. Display first 4 doctors who are earning least salary. Display details of all patients in such a way that female patients are shown before male patients. Display the unique cities from doctor table. Display all…
*SQL Query Required* Display schedule_id, source, destination and travel_time which has minimum travel time. Sort the result based on schedule id BUSES P BUS_NO number(11) SCHEDULE BUS NAME Varchar2(20) t varchar2(20) t SCHEDULE_ID TRAVEL DATE varchar2(3) date d varchar2(20) t DESTINATION varchar2(20) t TYPE TOTAL_SEATS number(11) # AVAIL_SEATS number(11) # SOURCE number(11) BU NO number(11) # BUS_NO P BUS NO DURATION PAYMENTS DISCOUNTS P PAYMENT_ID varchar2(3)t varchar2(3) number(11) varchar2(3) TICKET ID BD IDO O TICKET_ID oO BD_ID PDISCOUNT_ID DISCOUNT_AMOUNT number(11) # TICKETS O DISCOUNT_ID varchar2(3) SCOUNT_ID TICKET ID yarchar2(3) HEDULE ID O SCHEDULE ID varchar2(3) number(11) # number(11)O number(11) # FARE USER ID OUSER ID NO SEATS USERS PUSER_ID number(11) varchar2(20) t ADDRESS varchar2(100) t number(11) # EMAILID varchar2(30) t primary key - not null NAME e foreign key PHNO # data type - number d data type - date It| data type - varchar2 CANCELLATION PCANCELLATION_ID…
write an sql query that displays the parking space number location as well as the name of the staff member to whom the parking space has been allocated
By using this table answer this question in SQL: Show the department id, department name and the number of employees working in any department which has less than 4 employees
Database Q1: Select the correct SQL statement to provide the user Samer with read only permission on Employees table a) Grant read on Employee where username = Samer; b) Grant read only on Employee to Samer; c) Grant select to Samer on Employee; d) Grant select on Employee to Samer; Q2: Based on the TWO schema structures below, which SQL statement will create a view to show department names where each department has at least 5 employees? Employee (E_ID, E_Name, D_ID, E_Salary) Department (D_ID, D_Name, D_Address) (Select one) a) Create View Dept_Emp as select D_Name, count(E_ID) from Employee, Department where Employee D_ID = Department D_ID Group by D_Name Where count (E_ID) >= 5; b) Create View Dept_Emp as select D_Name, count(E_ID) from Employee D_ID = Department D_ID Group by D_Name Having count (E_ID) >= 5; c) Create View Dept_Emp as select D_Name, count(D_ID) from Employee, Department where Employee D_ID = Department D_ID Group by D_Name Having count (E_ID) >= 5; d)…