Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![**Title: Understanding SN2 Reaction Rates**
**Question:**
Which SN2 reaction in each pair is faster?
---
**Section A:**
1. **Reaction 1:**
- **Reactants:**
- 1-bromopentane
- Water (\(H_2O\))
- **Products:**
- Pentanol (\(OH_2^+\))
- Bromide ion (\(Br^-\))
2. **Reaction 2:**
- **Reactants:**
- 1-bromopentane
- Hydroxide ion (\(OH^-\))
- **Products:**
- Pentanol
- Bromide ion (\(Br^-\))
**Section B:**
1. **Reaction 1:**
- **Reactants:**
- 1-chloropentane
- Methoxide ion (\(OCH_3^-\))
- **Products:**
- Methoxy pentane
- Chloride ion (\(Cl^-\))
2. **Reaction 2:**
- **Reactants:**
- 1-iodopentane
- Hydroxide ion (\(OH^-\))
- **Products:**
- Pentanol
- Iodide ion (\(I^-\))
**Explanation:**
In SN2 reactions, the rate is influenced by the nucleophile strength, the leaving group ability, and solvent effects. Generally, stronger nucleophiles and better leaving groups increase reaction rates.
- **Section A:** Compare the nucleophiles—\(OH^-\) is stronger than \(H_2O\), suggesting Reaction 2 is faster.
- **Section B:** Consider the leaving groups—iodide (\(I^-\)) is a better leaving group than chloride (\(Cl^-\)), indicating Reaction 2 is faster in this case as well.
**Conclusion:**
For faster SN2 reactions, choose strong nucleophiles and substrates with good leaving groups.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F10109699-e850-457b-a56b-e064ba192cdf%2F25504133-1beb-4433-bfe8-3b6bd37c5289%2F7lcqhj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Title: Understanding SN2 Reaction Rates**
**Question:**
Which SN2 reaction in each pair is faster?
---
**Section A:**
1. **Reaction 1:**
- **Reactants:**
- 1-bromopentane
- Water (\(H_2O\))
- **Products:**
- Pentanol (\(OH_2^+\))
- Bromide ion (\(Br^-\))
2. **Reaction 2:**
- **Reactants:**
- 1-bromopentane
- Hydroxide ion (\(OH^-\))
- **Products:**
- Pentanol
- Bromide ion (\(Br^-\))
**Section B:**
1. **Reaction 1:**
- **Reactants:**
- 1-chloropentane
- Methoxide ion (\(OCH_3^-\))
- **Products:**
- Methoxy pentane
- Chloride ion (\(Cl^-\))
2. **Reaction 2:**
- **Reactants:**
- 1-iodopentane
- Hydroxide ion (\(OH^-\))
- **Products:**
- Pentanol
- Iodide ion (\(I^-\))
**Explanation:**
In SN2 reactions, the rate is influenced by the nucleophile strength, the leaving group ability, and solvent effects. Generally, stronger nucleophiles and better leaving groups increase reaction rates.
- **Section A:** Compare the nucleophiles—\(OH^-\) is stronger than \(H_2O\), suggesting Reaction 2 is faster.
- **Section B:** Consider the leaving groups—iodide (\(I^-\)) is a better leaving group than chloride (\(Cl^-\)), indicating Reaction 2 is faster in this case as well.
**Conclusion:**
For faster SN2 reactions, choose strong nucleophiles and substrates with good leaving groups.
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