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Which reagents will form the product shown in the reaction below? (only product formed) OH O a. H2O, A O b:H2SO4, H2O O C. 1. Hg(OAc)2, H2O; 2. NaBH4 O d. 1. ВНз:THF;B 2. Н2О2, NaOH О е. СН3ОН, д

Which reagents will form the product shown in the reaction below? (only product formed) OH O a. H2O, A O b:H2SO4, H2O O C. 1. Hg(OAc)2, H2O; 2. NaBH4 O d. 1. ВНз:THF;B 2. Н2О2, NaOH О е. СН3ОН, д

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Question:** Which reagents will form the product shown in the reaction below? **Reaction:** - Starting Material: An alkene - Product: An alcohol with its hydroxyl group on the less substituted carbon **Product (only product formed):** The structure shows an alcohol with a hydroxyl (OH) group added in a specific position indicative of anti-Markovnikov addition, likely through hydroboration-oxidation. **Options:** a. H₂O, Δ b. H₂SO₄, H₂O c. 1. Hg(OAc)₂, H₂O; 2. NaBH₄ d. **1. BH₃·THF; 2. H₂O₂, NaOH** (Correct Answer) e. CH₃OH, Δ **Explanation:** The correct reagents for forming the product via the anti-Markovnikov addition of water to an alkene are BH₃·THF followed by H₂O₂ and NaOH, which is option d. This process is known as hydroboration-oxidation.
Transcribed Image Text:**Question:** Which reagents will form the product shown in the reaction below? **Reaction:** - Starting Material: An alkene - Product: An alcohol with its hydroxyl group on the less substituted carbon **Product (only product formed):** The structure shows an alcohol with a hydroxyl (OH) group added in a specific position indicative of anti-Markovnikov addition, likely through hydroboration-oxidation. **Options:** a. H₂O, Δ b. H₂SO₄, H₂O c. 1. Hg(OAc)₂, H₂O; 2. NaBH₄ d. **1. BH₃·THF; 2. H₂O₂, NaOH** (Correct Answer) e. CH₃OH, Δ **Explanation:** The correct reagents for forming the product via the anti-Markovnikov addition of water to an alkene are BH₃·THF followed by H₂O₂ and NaOH, which is option d. This process is known as hydroboration-oxidation.
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