Which product(s) could possibly form in this reaction? There is excess NaOiPr available to react. Br NaOiPr Br isopropanol A. Isopropyl-(4-methyl-4-bromo-pentyl)ether. (OiPr replaces the Br on the right) B. 6-bromo-1-hexene C. 2-methyl-2,4-hexadiene D. the ether where the OiPr replaces the left Br O 1. Only D O 2. A, B, and C could all easily form 3. Only answer A 4. Only answer B and C
Reactive Intermediates
In chemistry, reactive intermediates are termed as short-lived, highly reactive atoms with high energy. They rapidly transform into stable particles during a chemical reaction. In specific cases, by means of matrix isolation and at low-temperature reactive intermediates can be isolated.
Hydride Shift
A hydride shift is a rearrangement of a hydrogen atom in a carbocation that occurs to make the molecule more stable. In organic chemistry, rearrangement of the carbocation is very easily seen. This rearrangement can be because of the movement of a carbocation to attain stability in the compound. Such structural reorganization movement is called a shift within molecules. After the shifting of carbocation over the different carbon then they form structural isomers of the previous existing molecule.
Vinylic Carbocation
A carbocation where the positive charge is on the alkene carbon is known as the vinyl carbocation or vinyl cation. The empirical formula for vinyl cation is C2H3+. In the vinyl carbocation, the positive charge is on the carbon atom with the double bond therefore it is sp hybridized. It is known to be a part of various reactions, for example, electrophilic addition of alkynes and solvolysis as well. It plays the role of a reactive intermediate in these reactions.
Cycloheptatrienyl Cation
It is an aromatic carbocation having a general formula, [C7 H7]+. It is also known as the aromatic tropylium ion. Its name is derived from the molecule tropine, which is a seven membered carbon atom ring. Cycloheptatriene or tropylidene was first synthesized from tropine.
Stability of Vinyl Carbocation
Carbocations are positively charged carbon atoms. It is also known as a carbonium ion.
![QUESTION 19
Which product(s) could possibly form in this reaction? There is excess NaOiPr available to react.
Br
NaOiPr
Br
isopropanol
A. Isopropyl-(4-methyl-4-bromo-pentyl)ether. (OiPr replaces the Br on the right)
B. 6-bromo-1-hexene
C. 2-methyl-2,4-hexadiene
D. the ether where the OiPr replaces the left Br
O 1. Only D
O 2. A, B, and C could all easily form
3. Only answer A
O 4. Only answer B and C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2b59f447-cc5a-4069-9325-1cb86a557765%2F3ddf1fdf-68b9-4030-9e8d-414866db9214%2Frr9dxt_processed.jpeg&w=3840&q=75)
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