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Which orbital type below does not exist due to wave-mechanical quantum number restrictions? 4p O 4d O 5s O 3f

Which orbital type below does not exist due to wave-mechanical quantum number restrictions? 4p O 4d O 5s O 3f

Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter6: Electronic Structure And The Periodic Table
Section: Chapter Questions
Problem 26QAP: How many electrons in an atom can have the following quantum designation? (a) 1s (b) 4d, m l =0(c)...
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**Question:** Which orbital type below does not exist due to wave-mechanical quantum number restrictions? - ○ 4p - ○ 4d - ○ 5s - ○ 3f **Explanation:** In quantum mechanics, orbitals are defined by quantum numbers that describe the properties of electrons within an atom. The principal quantum number (n) indicates the energy level, while the azimuthal quantum number (l) corresponds to the shape or type of orbital (s, p, d, f). For each principal quantum number (n), the azimuthal quantum number (l) can range from 0 up to n-1. Therefore: - For n = 4, possible l values are 0 (s), 1 (p), 2 (d), and 3 (f). - For n = 5, possible l values are 0 (s), 1 (p), 2 (d), 3 (f), and 4 (g). - For n = 3, possible l values are 0 (s), 1 (p), and 2 (d). The orbital "3f" is not possible because for n=3, l cannot be 3. Hence "3f" does not exist.
Transcribed Image Text:**Question:** Which orbital type below does not exist due to wave-mechanical quantum number restrictions? - ○ 4p - ○ 4d - ○ 5s - ○ 3f **Explanation:** In quantum mechanics, orbitals are defined by quantum numbers that describe the properties of electrons within an atom. The principal quantum number (n) indicates the energy level, while the azimuthal quantum number (l) corresponds to the shape or type of orbital (s, p, d, f). For each principal quantum number (n), the azimuthal quantum number (l) can range from 0 up to n-1. Therefore: - For n = 4, possible l values are 0 (s), 1 (p), 2 (d), and 3 (f). - For n = 5, possible l values are 0 (s), 1 (p), 2 (d), 3 (f), and 4 (g). - For n = 3, possible l values are 0 (s), 1 (p), and 2 (d). The orbital "3f" is not possible because for n=3, l cannot be 3. Hence "3f" does not exist.
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