Which one of the following statements is True?The Odds against A equals 1 – Odds in favor of A.For a mound shaped distribution if the skew is positive then the mean is greater than the median.P(n, r) = C(n, r) / r!The probability of an event equals the number of favorable outcomes divided by the number of unfavorable outcomes.A Bimodal distribution is symmetric.

Statement 1 : False Odds in favor of A = Favorable outcomesUnfavorable outcomes Odds in against A…

Answered: Which one of the following statements…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Which one of the following statements is True?

The Odds against A equals 1 – Odds in favor of A.
For a mound shaped distribution if the skew is positive then the mean is greater than the median.
P(n, r) = C(n, r) / r!
The probability of an event equals the number of favorable outcomes divided by the number of unfavorable outcomes.
A Bimodal distribution is symmetric.

Definition Definition Middle value of a data set. The median divides a data set into two halves, and it also called the 50th percentile. The median is much less affected by outliers and skewed data than the mean. If the number of elements in a dataset is odd, then the middlemost element of the data arranged in ascending or descending order is the median. If the number of elements in the dataset is even, the average of the two central elements of the arranged data is the median of the set. For example, if a dataset has five items—12, 13, 21, 27, 31—the median is the third item in ascending order, or 21. If a dataset has six items—12, 13, 21, 27, 31, 33—the median is the average of the third (21) and fourth (27) items. It is calculated as follows: (21 + 27) / 2 = 24.

Expert Solution

Step 1

Statement 1 : False

$O d d s i n f a v o r o f A = \frac{F a v o r a b l e o u t c o m e s}{U n f a v o r a b l e o u t c o m e s}$

$O d d s i n a g a i n s t A = \frac{U n f a v o r a b l e o u t c o m e s}{F a v o r a b l e o u t c o m e s}$

Statement 2 : True.

For positive skewed distribution : Mode < median < mean
For symmetric distribution : Mode = mean = Median
For negative skewed distribution : Mode > median > mean

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