Which one of the following represents simple harmonic motion? a) Acceleration = kx b) Acceleration = k0 x+k1 x2 c) Acceleration = -k(x+a) d) Acceleration = k(x+a)
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Which one of the following represents
a) Acceleration = kx
b) Acceleration = k0 x+k1 x2
c) Acceleration = -k(x+a)
d) Acceleration = k(x+a)
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- Thank you in advance!3) OK, once again we have a pendulum, this time of length 1.94 m, which you release from rest at an angle of 59.1 degrees to the vertical. What will be the speed of the pendulum at the instant it reaches an angle of 29.6 degrees above the vertical? Question 2 options: 6.88 m/s 3.68 m/s 4.30 m/s 2.23 m/s 4) This, the length of the pendulum is 2.17 m. Now you start with the pendulum at 10.2 degrees with respect to the vertical, but rather than releasing it from rest, you give it a push downward. It swings to the other side, and reaches a maximum angle of 34.0 degrees with respect to the vertical. What must have been the initial speed of the pendulum just after you pushed it? 2.70 m/s 0.82 m/s 3.51 m/s 2.57 m/sThe graph shows the position of an object in simple harmonic motion. At which labeled point is the instantaneous velocity zero while the acceleration is in the negative direction? A O A OB O E O с x (m) D B 1 2 3 D E t(s)
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