Which one of the following equilibria would not be affected by volume changes at constant temperature? a) 2CO (g) + O2 (g) < -- > 2CO2 (g) b) 2NO2 (g) < -- > N204 (g) c) 2 NO (g) + 3F2 (g) < -- > 2F3NO (g) d) BF3 (g) + NH3 (g) < -- > H3NBF3 (g) e) O3 (g) + NO (g) < -- > NO2 (g) + O2 (g)

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### Equilibrium and Volume Changes

**Question:**  
Which one of the following equilibria would **not** be affected by volume changes at constant temperature?

**Options:** 
a) \(2\text{CO (g)} + \text{O}_2 (\text{g}) \leftrightarrow 2\text{CO}_2 (\text{g})\)  
b) \(2\text{NO}_2 (\text{g}) \leftrightarrow \text{N}_2\text{O}_4 (\text{g})\)  
c) \(2 \text{NO (g)} + 3\text{F}_2 (\text{g}) \leftrightarrow 2 \text{F}_3\text{NO (g)}\)  
d) \(\text{BF}_3 (\text{g}) + \text{NH}_3 (\text{g}) \leftrightarrow \text{H}_3\text{NBF}_3 (\text{g})\)  
e) \(\text{O}_3 (\text{g}) + \text{NO (g)} \leftrightarrow \text{NO}_2 (\text{g}) + \text{O}_2 (\text{g})\)  

### Explanation of Answer:

#### Key Concept:
In chemical equilibrium, the response to volume changes depends on the number of moles of gas on either side of the equilibrium equation. According to Le Chatelier's Principle, the position of equilibrium shifts in response to volume changes in order to counteract those changes. If the number of moles of gases is the same on both sides, then changes in volume will have no effect on the equilibrium position.

#### Solution:
a) \(2\text{CO (g)} + \text{O}_2 (\text{g}) \leftrightarrow 2\text{CO}_2 (\text{g}) \)  
   Total moles of gas on left = 3  
   Total moles of gas on right = 2  
   **Affected by volume changes**

b) \(2\text{NO}_2 (\text{g}) \leftrightarrow \text{N}_2\text{O}_4 (\text{g})\)  
   Total moles of gas on left = 2  
   Total moles of gas on right =
Transcribed Image Text:### Equilibrium and Volume Changes **Question:** Which one of the following equilibria would **not** be affected by volume changes at constant temperature? **Options:** a) \(2\text{CO (g)} + \text{O}_2 (\text{g}) \leftrightarrow 2\text{CO}_2 (\text{g})\) b) \(2\text{NO}_2 (\text{g}) \leftrightarrow \text{N}_2\text{O}_4 (\text{g})\) c) \(2 \text{NO (g)} + 3\text{F}_2 (\text{g}) \leftrightarrow 2 \text{F}_3\text{NO (g)}\) d) \(\text{BF}_3 (\text{g}) + \text{NH}_3 (\text{g}) \leftrightarrow \text{H}_3\text{NBF}_3 (\text{g})\) e) \(\text{O}_3 (\text{g}) + \text{NO (g)} \leftrightarrow \text{NO}_2 (\text{g}) + \text{O}_2 (\text{g})\) ### Explanation of Answer: #### Key Concept: In chemical equilibrium, the response to volume changes depends on the number of moles of gas on either side of the equilibrium equation. According to Le Chatelier's Principle, the position of equilibrium shifts in response to volume changes in order to counteract those changes. If the number of moles of gases is the same on both sides, then changes in volume will have no effect on the equilibrium position. #### Solution: a) \(2\text{CO (g)} + \text{O}_2 (\text{g}) \leftrightarrow 2\text{CO}_2 (\text{g}) \) Total moles of gas on left = 3 Total moles of gas on right = 2 **Affected by volume changes** b) \(2\text{NO}_2 (\text{g}) \leftrightarrow \text{N}_2\text{O}_4 (\text{g})\) Total moles of gas on left = 2 Total moles of gas on right =
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