Which of the results calculated and listed below is correct for the unknown forces shown in the FBD? P, 5 kN P₂ = 10 kN. J = 21.25 kN a2 m. a; 1 m, as 0.5 m a 1 m. a; -2.5 m Angle FGH makes with the horizontal is: 26.57 degrees Angle FGB makes with the horizontal is-tan (1.5/2) P₁ KN P₂ KN am am 8 M 8m B Ea Fox Select one or more a. FCB=-4.00 kN Correct: this example shows the correct calculation for the force named, well done. b. Fax = 14.5 kN Correct; this example shows the correct calculation for the force named, well done. CFc-173 kN d. F = 21.3 kN Correct this example shows the correct calculation for the force named, well done. e. Fat=37.9 kN f. Fou--14.5 kN 9. Fa=13.0 kN h. Fox=-13.0 kN iFca - 43.3 kN DELL

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Chapter6: Applications Of Newton's Laws
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Please help me to find Fgb force.
Which of the results calculated and listed below is correct for the unknown forces shown in the FBD?
P, 5 kN P₂ = 10 kN. J = 21.25 kN
a2 m. a; 1 m, as 0.5 m a 1 m. a; -2.5 m
Angle FGH makes with the horizontal is: 26.57 degrees
Angle FGB makes with the horizontal is-tan (1.5/2)
P₁ KN P₂ KN
am
am
8 M
8m
B
Ea
Fox
Select one or more
a. FCB=-4.00 kN Correct: this example shows the correct calculation for the force named, well done.
b. Fax = 14.5 kN Correct; this example shows the correct calculation for the force named, well done.
CFc-173 kN
d. F = 21.3 kN Correct this example shows the correct calculation for the force named, well done.
e. Fat=37.9 kN
f. Fou--14.5 kN
9. Fa=13.0 kN
h. Fox=-13.0 kN
iFca - 43.3 kN
DELL
Transcribed Image Text:Which of the results calculated and listed below is correct for the unknown forces shown in the FBD? P, 5 kN P₂ = 10 kN. J = 21.25 kN a2 m. a; 1 m, as 0.5 m a 1 m. a; -2.5 m Angle FGH makes with the horizontal is: 26.57 degrees Angle FGB makes with the horizontal is-tan (1.5/2) P₁ KN P₂ KN am am 8 M 8m B Ea Fox Select one or more a. FCB=-4.00 kN Correct: this example shows the correct calculation for the force named, well done. b. Fax = 14.5 kN Correct; this example shows the correct calculation for the force named, well done. CFc-173 kN d. F = 21.3 kN Correct this example shows the correct calculation for the force named, well done. e. Fat=37.9 kN f. Fou--14.5 kN 9. Fa=13.0 kN h. Fox=-13.0 kN iFca - 43.3 kN DELL
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