Which of the reactions are exothermic?2 Mg(s) + O₂(g) -NH3(g) + HCl(g)-> NH₂Cl(s) + heatAgCl(s) + heat.-> Ag+ (aq) + Cl(aq)2 Fe₂O3(s) + 3 C(s) + heat 4 Fe(s) + 3 CO₂(g)- 2 MgO(s) + heatC(graphite) + O₂(g) → CO₂(g) + heat- -✓CH₂(g) + 2O₂(g) → CO₂(g) + 2 H₂O(1) + heat->Incorrect

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Answered: Which of the reactions are exothermic?…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Consider these reactions, where M represents a generic metal. 1. 2 M(s) + 6 HCI(aq) → 2 MCl, (aq) + 3 H, (g) AH1 = -789.0 kJ 2. HCl(g) HCl(aq) ΔΗ = -74.8 kJ 3. H, (g) + Cl, (g) → 2 HCl(g) AH3 = -1845.0 kJ 4. MCI, (s) → MCl, (aq) ΔΗ4 = -418.0 kJ Use the given information to determine the enthalpy of the reaction 2 M(s) + 3 Cl, (g) → 2 MCI, (s)
Classify the reaction endothermic or exothermic and give the change in enthalpy of the reaction. CH3OH (1) + 3 O₂ (g) → 2 CO₂ (g) + 4 H₂O (g) Δ Η = -557 kJ The heat energy in the reaction is Select an answer This makes the reaction Select an answer So, the energy would be on the Select an answer side.
48.2 mL of a solution of HCl is combined with 110.7 mL of 1.35 M NaOH in a calorimeter. The reaction mixture is initially at 22.4°C, and the final temperature after reaction is 29.3°C. What is the molarity of the HCl solution? You may assume that there is an excess of base (so that all the HCI has reacted), that the specific heat of the reaction mixture is 0.96 cal/g °C, and that the density of the reaction mixture is 1.02 g/mL. The heat of neutralization of HCl and NaOH is 13.6 kcal/mole.
The reaction between HCl and NaOH is represented below. When equal volumes of 1.00 M NaOH and 1.00 M HCl are mixed, 57.1 kJ of heat is released. What would A H be if 2.00 M HCI and 2.00 M NaOH is used instead of 1.00 M? HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l) AH = -57.1 kJ/mol... (A) - 28.6 kJ B-85.7 kJ (c) -57.1 kJ D - 114 kJ
Consider these reactions, where M represents a generic metal. 1. 2 M(s) + 6 HC1(aq) → 2 MCl,(aq) + 3 H,(g) ΔΗ = -589.0 kJ 2. HCI(g) → HCI(aq) AH2 = -74.8 kJ 3. H,(g) + Cl,(g) –→ 2 HCI(g) AH3 = -1845.0 kJ 4. MCI,(s) → MCl,(aq) AH4 = -262.0 kJ Use the given information to determine the enthalpy of the reaction 2 M(s) + 3 Cl,(g) → 2 MCl,(s) ΔΗ- kJ
q represents the change in heat of a reaction or substance. The units of q are Joules (J) or kilojoules (kJ). For a well understood substance, we can calculate the specific heat which relates the mass of the substance in grams to the amount of heat in J required to raise that amount a certain temperature. We call that specific heat. The specific heat (Cs) of water is stated in the following way: C s ( H 2 O ) = 4.186 J g ∘ C This means that it takes 4.186 J of energy to raise the temperature of 1g of water by 1ºC. The relationship between q and Cs for a given substance is where m is mass (g) and ∆T is the change in temperature in ºC (final temp - initial temp). Calculate the heat change (q) in J when 4.297 grams of water is cooled from 3.967 ºC to -2.902 ºC. Enter your answer with one decimal place (tenths). Pay careful attention to the sign of your answer. The sign of ∆T is always the same as the sign for q.
Calculate the heat of reaction (in J)
500.0 mL of 0.100 mol·L HCl(aq) was added to a high quality insulated calorimeter containing 500.0 mL of 0.100 mol·LNaOH(aq). Both solutions had a density of 1.000 g·mL and a specific heat of 4.184 J·g ·K . The calorimeter had a heatcapacity of 850.0 J·K . The temperature of the entire system rose from 25.50 C to 26.05 C.Calculate the heat of reaction. Thank you!
Which of the following reactions is exothermic? C2H4(g) + O2(g) → 2C(s) + 2H2O(g) AH = 469.2 kJ O N204(g) + 57.6 kJ → 2NO2(g) C2H4(g) + 302(g) → 2CO2(g) + 2H2O(g) > AH = 1322.9 kJ PCI3(g) + Cl2(g)→ PCI5(g) + 92.5 kJ
Which reaction would it be possible to calculate (Triangle H)?
CH, (g) 20, (g) → CO, (g) + 2 H,O (g) + Exothermic or endothermic
Calculate AH for the reaction P4010(s) + 6PC15(g) – 10C13PO(g) given, P4(s) + 6C12(g) → 4PC13(g) AH = -1225.6 kJ P4(s) + 502(g) – P4010(s) AH = -2967.3 kJ PC13(g) + Cl2(g) → PC15(g) AH = -84.2 kJ PC13(g) + (1/2)02(g) – C13PO(g) AH=-285.7 kJ ΔΗ- kJ

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