Which of the following vectors is orthogonal to the plane 3(x - 7) + (y + 8) - 5z = 15? O <7,-8, 0> O <- 7, 8, 0> O <3, 1, - 5> <- - 3, -1, 5>

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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### Question:
**Which of the following vectors is orthogonal to the plane 3(x - 7) + (y + 8) - 5z = 15?**

### Answer Choices:
- ☐ \( \langle 7, -8, 0 \rangle \)
- ☐ \( \langle -7, 8, 0 \rangle \)
- ☐ \( \langle 3, 1, -5 \rangle \)
- ☐ \( \langle -3, -1, 5 \rangle \)
- ☐ None of these

### Explanation:
To determine which of the given vectors is orthogonal to the plane, we need to check if any of the vectors match the normal vector of the plane. The equation of the plane given is in the form:

\[ 3(x - 7) + (y + 8) - 5z = 15 \]

By expanding and rewriting this equation, we get:

\[ 3x - 21 + y + 8 - 5z = 15 \implies 3x + y - 5z - 13 = 0 \]

The coefficients of \( x \), \( y \), and \( z \) in the equation represent the components of the normal vector to the plane. Thus, the normal vector is:

\[ \langle 3, 1, -5 \rangle \]

Therefore, the vector orthogonal to the plane is:

**\( \langle 3, 1, -5 \rangle \)**

Hence, the correct answer is the third option.
Transcribed Image Text:### Question: **Which of the following vectors is orthogonal to the plane 3(x - 7) + (y + 8) - 5z = 15?** ### Answer Choices: - ☐ \( \langle 7, -8, 0 \rangle \) - ☐ \( \langle -7, 8, 0 \rangle \) - ☐ \( \langle 3, 1, -5 \rangle \) - ☐ \( \langle -3, -1, 5 \rangle \) - ☐ None of these ### Explanation: To determine which of the given vectors is orthogonal to the plane, we need to check if any of the vectors match the normal vector of the plane. The equation of the plane given is in the form: \[ 3(x - 7) + (y + 8) - 5z = 15 \] By expanding and rewriting this equation, we get: \[ 3x - 21 + y + 8 - 5z = 15 \implies 3x + y - 5z - 13 = 0 \] The coefficients of \( x \), \( y \), and \( z \) in the equation represent the components of the normal vector to the plane. Thus, the normal vector is: \[ \langle 3, 1, -5 \rangle \] Therefore, the vector orthogonal to the plane is: **\( \langle 3, 1, -5 \rangle \)** Hence, the correct answer is the third option.
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