Which of the following statements about enthalpy is false? Because E, P, and V are all state functions, H is also a state function. O Under constant pressure, AH = AE+PAV. Enthalpy is denoted H. O AH equals the heat gained or lost in a process that occurs at constant pressure. O Because AH relates to heat, the value of AH depends on the path taken between two states.

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Question:**

Which of the following statements about enthalpy is false?

**Options:**

- ○ Because \( E \), \( P \), and \( V \) are all state functions, \( H \) is also a state function.
- ○ Under constant pressure, \(\Delta H = \Delta E + P \Delta V\).
- ○ Enthalpy is denoted \( H \).
- ○ \(\Delta H\) equals the heat gained or lost in a process that occurs at constant pressure.
- ○ Because \(\Delta H\) relates to heat, the value of \(\Delta H\) depends on the path taken between two states.

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Transcribed Image Text:**Question:** Which of the following statements about enthalpy is false? **Options:** - ○ Because \( E \), \( P \), and \( V \) are all state functions, \( H \) is also a state function. - ○ Under constant pressure, \(\Delta H = \Delta E + P \Delta V\). - ○ Enthalpy is denoted \( H \). - ○ \(\Delta H\) equals the heat gained or lost in a process that occurs at constant pressure. - ○ Because \(\Delta H\) relates to heat, the value of \(\Delta H\) depends on the path taken between two states. **Actions:** - [Submit] - [Request Answer]
**Thermodynamics Problem: Understanding Heat and Work Sign Conventions**

**Part B**

Determine the conditions under which the quantity \( q \) (heat) will be negative and the quantity \( w \) (work) will be positive.

Options:
1. \( q \) is negative when the system loses heat to the surroundings, \( w \) is positive when the surroundings do work on the system.
2. \( q \) is negative when the system loses heat to the surroundings, \( w \) is positive when the system does work on the surroundings. *(Selected)*
3. \( q \) is negative when the system gains heat from the surroundings, \( w \) is positive when the system does work on the surroundings.
4. \( q \) is negative when the system gains heat from the surroundings, \( w \) is positive when the surroundings do work on the system.

**Current Status:**  
- Feedback: Incorrect  
- Attempts Remaining: 2

**Explanation:**

In thermodynamics, heat (\( q \)) is considered negative when it is lost from the system to its surroundings. Work (\( w \)) is considered positive when the system performs work on the surroundings. The selected option interprets these conventions but was marked incorrect, indicating a need for review.
Transcribed Image Text:**Thermodynamics Problem: Understanding Heat and Work Sign Conventions** **Part B** Determine the conditions under which the quantity \( q \) (heat) will be negative and the quantity \( w \) (work) will be positive. Options: 1. \( q \) is negative when the system loses heat to the surroundings, \( w \) is positive when the surroundings do work on the system. 2. \( q \) is negative when the system loses heat to the surroundings, \( w \) is positive when the system does work on the surroundings. *(Selected)* 3. \( q \) is negative when the system gains heat from the surroundings, \( w \) is positive when the system does work on the surroundings. 4. \( q \) is negative when the system gains heat from the surroundings, \( w \) is positive when the surroundings do work on the system. **Current Status:** - Feedback: Incorrect - Attempts Remaining: 2 **Explanation:** In thermodynamics, heat (\( q \)) is considered negative when it is lost from the system to its surroundings. Work (\( w \)) is considered positive when the system performs work on the surroundings. The selected option interprets these conventions but was marked incorrect, indicating a need for review.
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