Which of the following solutions of strong electrolytes contains the largest number of ions? O 400.0 mL of 0.100 M KI O 200.0 mL of 0.200 M CaCl2 O 300.0 mL of 0.150 M CS3PO,

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Chapter1: Chemical Foundations
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**Question:**

Which of the following solutions of strong electrolytes contains the largest number of ions?

- 400.0 mL of 0.100 M KI
- 200.0 mL of 0.200 M CaCl₂
- 300.0 mL of 0.150 M Ca₃(PO₄)₂

**Explanation:**

Each option provides a different solution of a strong electrolyte with specific molarity and volume. The task is to determine which solution results in the largest number of ions when dissolved in water.

1. **Potassium Iodide (KI)** dissociates into K⁺ and I⁻, giving 2 ions per formula unit.
2. **Calcium Chloride (CaCl₂)** dissociates into Ca²⁺ and 2 Cl⁻, giving 3 ions per formula unit.
3. **Calcium Phosphate (Ca₃(PO₄)₂)** dissociates into 3 Ca²⁺ and 2 PO₄³⁻, giving 5 ions per formula unit.

To find the number of ions, calculate the total moles of ions produced using the formula: (volume in liters) × (molarity) × (number of ions per dissociation).

Compare the results to find which solution has the highest number of total ions.
Transcribed Image Text:**Question:** Which of the following solutions of strong electrolytes contains the largest number of ions? - 400.0 mL of 0.100 M KI - 200.0 mL of 0.200 M CaCl₂ - 300.0 mL of 0.150 M Ca₃(PO₄)₂ **Explanation:** Each option provides a different solution of a strong electrolyte with specific molarity and volume. The task is to determine which solution results in the largest number of ions when dissolved in water. 1. **Potassium Iodide (KI)** dissociates into K⁺ and I⁻, giving 2 ions per formula unit. 2. **Calcium Chloride (CaCl₂)** dissociates into Ca²⁺ and 2 Cl⁻, giving 3 ions per formula unit. 3. **Calcium Phosphate (Ca₃(PO₄)₂)** dissociates into 3 Ca²⁺ and 2 PO₄³⁻, giving 5 ions per formula unit. To find the number of ions, calculate the total moles of ions produced using the formula: (volume in liters) × (molarity) × (number of ions per dissociation). Compare the results to find which solution has the highest number of total ions.
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