**Conversion Problem:****Question:**Which of the following series of mathematical operations would convert 0.45 miles into centimeters?**Conversion Factors:**- 1 inch (in) = 2.54 centimeters (cm)- 1 mile (mi) = 1.61 kilometers (km)- 1 mile (mi) = 5280 feet (ft)- 1 ounce (oz) = 28.3 grams (g)- 1 ton = 2000 pounds (lb)- 1 quart (qt) = 0.946 liters (L)- 1 liter (L) = 1.06 quarts (qt)- 1 milliliter (mL) = 20 drops- 1 pound (lb) = 454 grams (g)- 1 kilogram (kg) = 2.2 pounds (lbs)**Options:**1. \[\left(\frac{0.45 \, \text{mi}}{1}\right) \times \left(\frac{5280 \, \text{ft}}{1 \, \text{mi}}\right) \times \left(\frac{1 \, \text{in}}{12 \, \text{ft}}\right) \times \left(\frac{1 \, \text{cm}}{2.54 \, \text{in}}\right)\]2. \[\left(\frac{0.45 \, \text{mi}}{1}\right) \times \left(\frac{5280 \, \text{ft}}{1 \, \text{mi}}\right) \times \left(\frac{1 \, \text{ft}}{12 \, \text{in}}\right) \times \left(\frac{2.54 \, \text{cm}}{1 \, \text{in}}\right)\]3. \[\left(\frac{0.45 \, \text{mi}}{1}\right) \times \left(\frac{5280 \, \text{ft}}{1 \, \text{mi}}\right) \times \left(\frac{12 \, \text{in}}{1 \, \text{ft}}\right) \times \left(\frac{2.54 \, \text{cm}}{1 \

To solve this problem we have to do the given unit conversion.

Which of the following series of mathematical operations would convert 0.45 miles into centimeters? 1.qt = 0.946 L 1 in 2.54 cm 1 mi= 1.61 km 1 L = 1.06 qt 1 mL =20drops 1 mi=5280 feet 1 oz = 28.3 g 1 lb = 454 g 1 ton = 2000lb 1kg = 2.2 lbs 0 (0.45m²) x (520) <(1271)x (2.54m O 5280ft lin 1cm 1mi 12ft O (0.45mi)x( O 0.45mi 5280ft 12in 1mi 5280ft 1ft 1mi ²)×( 12in X 2.54cm 1in 2.54cm lin 1ft 1cm 0 (0.45m²) x ($250f) × ( 12 ) × (z 1mi 12in 2.54in

Which of the following series of mathematical operations would convert 0.45 miles into centimeters? 1.qt = 0.946 L 1 in 2.54 cm 1 mi= 1.61 km 1 L = 1.06 qt 1 mL =20drops 1 mi=5280 feet 1 oz = 28.3 g 1 lb = 454 g 1 ton = 2000lb 1kg = 2.2 lbs 0 (0.45m²) x (520) <(1271)x (2.54m O 5280ft lin 1cm 1mi 12ft O (0.45mi)x( O 0.45mi 5280ft 12in 1mi 5280ft 1ft 1mi ²)×( 12in X 2.54cm 1in 2.54cm lin 1ft 1cm 0 (0.45m²) x ($250f) × ( 12 ) × (z 1mi 12in 2.54in

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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