Which of the following represents the volume of the solid generated by revolving the region bounded by f(x)=(x-1)³ and g(x)=x-1 about the x-axis? 2 A 2π 2n x[(x-1) ³- (x-1)]dx + 2x *x[(x-1)=(x-1) ³]dx 2 ℗ 2x * x[(x-1) - (x-1)³²]dx + 2x [²x [(x− 1)³= (x-1)}]dx B (x− x[(x-1)³- Ⓒ = √ [(x-1)³²- C * S * [(x − 1)² = (x-1) 6]dx + x^² [(x-1)²-(x-1)]dx D TU 1 ² [(x − 1)² – (x - 2) - - − 1)²]dx - ₁²[(x − 1)²-(x - 1)]dx
Which of the following represents the volume of the solid generated by revolving the region bounded by f(x)=(x-1)³ and g(x)=x-1 about the x-axis? 2 A 2π 2n x[(x-1) ³- (x-1)]dx + 2x *x[(x-1)=(x-1) ³]dx 2 ℗ 2x * x[(x-1) - (x-1)³²]dx + 2x [²x [(x− 1)³= (x-1)}]dx B (x− x[(x-1)³- Ⓒ = √ [(x-1)³²- C * S * [(x − 1)² = (x-1) 6]dx + x^² [(x-1)²-(x-1)]dx D TU 1 ² [(x − 1)² – (x - 2) - - − 1)²]dx - ₁²[(x − 1)²-(x - 1)]dx
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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34
![Which of the following represents the volume of the solid generated by revolving the region bounded by
f(x)=(x-1)³ and g(x)=x-1 about the x-axis?
2
Ⓒ 2n/"^x [(x-1) ³3-(x-1)]dx + 2x [*²x[(x− 1) = (x-1) ³]dx
A
℗ 2x^x[(x-1)-(x-1) ²]dx + 2x^x[(x-1) ³- (x− 1) ]dx
B
C
z ["* [(x − 1)² = (x− 1) º ]dx + x["{[(x− 1)² – (x− 1) ª]dx
,1
D
π [(x - 1) - (x - 1)²]dx - √ [(x − 1)² – (x - 1)]dx](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2ce40496-5709-4e96-82a7-6e2420bd366f%2F237b35b3-5a12-4469-8929-5eaa783be5e3%2Fde1hak_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Which of the following represents the volume of the solid generated by revolving the region bounded by
f(x)=(x-1)³ and g(x)=x-1 about the x-axis?
2
Ⓒ 2n/"^x [(x-1) ³3-(x-1)]dx + 2x [*²x[(x− 1) = (x-1) ³]dx
A
℗ 2x^x[(x-1)-(x-1) ²]dx + 2x^x[(x-1) ³- (x− 1) ]dx
B
C
z ["* [(x − 1)² = (x− 1) º ]dx + x["{[(x− 1)² – (x− 1) ª]dx
,1
D
π [(x - 1) - (x - 1)²]dx - √ [(x − 1)² – (x - 1)]dx
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