Which of the following rational functions is equivalent to the partial fraction decomposition 2x 2x - 1 3x 3x - 1

Graph f(x)=x2+2x3 by using transformations.

Find all real zeros of fx=8x34x2+6x3.

Write the following rational function as a sum of partial functions: 5s² +8s-5 ,2 s² (s² +2s+5)

x* + 9x2 + x + 2 is The rational function improper and the partial fraction can be written as: x2 + 9 Ax + B where A= [ Select ] and B = [ Select ] x2 + 9

Determine the coefficients of the rational expression below when expanded into partial fractions of the form: x²+2x-5 B x+2 x(x²2-4) X + + C x-2

Expand the following rational function using Partial fractions Step 2 x-1 (Y-1) (x+1) B. 1. (X-1)(x+) X-1 : A(x+1) +B(x-1) (ス-1)(M+) (X-1) (x+1) |- A(x+) + B(x- 1) Please explam 1Hiese Steps in detail ļ 1- x(A+B) + (A-B) Comparing. How do I AtB=0:-0 get to these steps. A -B= 1 0: A+B) A=-B. - B- 13:) ) 13 = - Omay こ (X-1) (x+1) 2(X-1) Ang 고

Vrite the polynomial P(x) = x-1 as a linear combination of P1(x) = 1-x+ 3x and P2(x) = 1-x+ 2x OA. p= P1-3P2 OB.p 2p1+3P O C. No correct answer D.p = 2p1-3p2 OE. p = 3p1-2p2

fx+ h) -f(x) hz 0. Compute and simplify the difference quotient f0) = 8-X Select one: OA. (8-x+h)(8-x) OB. hx (8-x-h)(8+x) 8. (8-x+h)(8-x) O C 8. OD. (8-x-h)(8-x)

Let f(x) = x³ 6x In x + 6x + 1000. Find all x-coordinates of the inflection points. O x = -1 and x = 1 O x= -2 and x = 0 O x = 1 and x = 2 O x = -2 and x = 1 O x= 2 and x = 4 O x = 0 and x = 1