Which of the following Python expressions long divides x by y, discards the quotient. keeps the remainder, and then raises that value to an exponent of z? O(x / y) ** z O(x ** z) % y O(x // y) ** z O(x % y) ** z O((x / y) - (x % y)) **
Which of the following Python expressions long divides x by y, discards the quotient. keeps the remainder, and then raises that value to an exponent of z? O(x / y) ** z O(x ** z) % y O(x // y) ** z O(x % y) ** z O((x / y) - (x % y)) **
C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter18: Stacks And Queues
Section: Chapter Questions
Problem 9SA
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Questions are in python. Thanks.
![Which of the following Python expressions long divides x by y, discards the quotient,
keeps the remainder, and then raises that value to an exponent of z?
O(x / y)
(x ** z) % y
O (x // y) ** z
O(x y) ** z
O((x / y) - (x % y)) ** z
** Z
ONone of these options](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F15eb9198-d198-4a17-8396-aa3ae1e6e709%2F2a1eec94-efa3-4b93-b5fd-c622ef202341%2Fyi2yz7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Which of the following Python expressions long divides x by y, discards the quotient,
keeps the remainder, and then raises that value to an exponent of z?
O(x / y)
(x ** z) % y
O (x // y) ** z
O(x y) ** z
O((x / y) - (x % y)) ** z
** Z
ONone of these options
![If the user types "5" at the "xx?" prompt, then what would be the output of the
following program?
aa = 8
XX =
int(input("xx?"))
jj
for i in range(2, xx, 2):
=21
jj += i
aа - a + 2
last digit
print (last digit)
(aa + jj) % 10](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F15eb9198-d198-4a17-8396-aa3ae1e6e709%2F2a1eec94-efa3-4b93-b5fd-c622ef202341%2Fl1tyro_processed.jpeg&w=3840&q=75)
Transcribed Image Text:If the user types "5" at the "xx?" prompt, then what would be the output of the
following program?
aa = 8
XX =
int(input("xx?"))
jj
for i in range(2, xx, 2):
=21
jj += i
aа - a + 2
last digit
print (last digit)
(aa + jj) % 10
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