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Which of the following mechanisms is drawn correctly? Remember to check arrows, formal charges, stereochemistry, and intermediates (if any). A. B. Me C. Me Me D. Me O: Al(OiPr)2 O Me Me Me Al(OiPr) 2 -Me Me Me Al(OiPr)2 O. -Me Me Me Al(OiPr)2 O -Me Me Me (OiPr)₂Al (OiPr)₂Al Me (OiPr)₂AK Me (OiPr)₂AK Me Me O Me Me H H Me Me Me -Me Me H -Me -Me Me -Me Me H Me Me (OiPr)₂Al Me (OiPr)₂Al O Me Al(OiPr)2 Me Al(OiPr)2 Me Me Me Me Me Me Me

Which of the following mechanisms is drawn correctly? Remember to check arrows, formal charges, stereochemistry, and intermediates (if any). A. B. Me C. Me Me D. Me O: Al(OiPr)2 O Me Me Me Al(OiPr) 2 -Me Me Me Al(OiPr)2 O. -Me Me Me Al(OiPr)2 O -Me Me Me (OiPr)₂Al (OiPr)₂Al Me (OiPr)₂AK Me (OiPr)₂AK Me Me O Me Me H H Me Me Me -Me Me H -Me -Me Me -Me Me H Me Me (OiPr)₂Al Me (OiPr)₂Al O Me Al(OiPr)2 Me Al(OiPr)2 Me Me Me Me Me Me Me

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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### Organic Chemistry Mechanism Analysis **Question:** Which of the following mechanisms is drawn correctly? Remember to check arrows, formal charges, stereochemistry, and intermediates (if any). **Mechanisms:** **Option A:** 1. The first step shows the attack of the oxygen lone pair on the Al of the Al(OiPr)2 group. 2. The second step presents the intermediate where the oxygen is protonated, and the Al carries a positive formal charge with a corresponding negative formal charge on oxygen. 3. The final step shows the departure of the Al(OiPr)2 group, leaving a double bond-forming product. **Option B:** 1. Like option A, the first step involves an attack from the oxygen lone pair on the Al of the Al(OiPr)2 group. 2. The intermediate structure also shows the oxygen protonated with charges similar to option A. 3. The final product formation matches what is shown in option A. **Option C:** 1. The first step is identical to options A and B with the oxygen lone pair attacking the Al of the Al(OiPr)2 group. 2. The intermediate correctly depicts the protonation with formal charges. 3. In the final product, the leaving of the Al(OiPr)2 group is illustrated, completing the mechanism properly. **Option D:** 1. The initial step mirrors the attack mechanism seen in previous options. 2. The intermediate is shown appropriately with correct formal charges. 3. The final product shows the departure of the Al(OiPr)2 group, forming the product structure correctly. **Conclusion:** All options show the same types of steps: initial oxygen lone pair attack on Al, intermediate formation with corresponding charges, and final product formation. However, option D shows the product forming in correct sequence and charge balance. Therefore, **Option D** illustrates the mechanism that is drawn correctly considering the arrows, formal charges, and intermediates. ### Diagram Explanation: - **Arrows:** Indicate the movement of electron pairs. Ensure that arrowheads point from electron donors (nucleophiles) to electron acceptors (electrophiles). - **Formal Charges:** Denoted on atoms for each intermediate, adhere to proper charge balance conservation through each step. - **Intermediates:** Transitional species appearing between the initial and final structures of the reactants and products. This analysis helps in understanding step-by-step reaction mechanisms crucial for learning organic
Transcribed Image Text:### Organic Chemistry Mechanism Analysis **Question:** Which of the following mechanisms is drawn correctly? Remember to check arrows, formal charges, stereochemistry, and intermediates (if any). **Mechanisms:** **Option A:** 1. The first step shows the attack of the oxygen lone pair on the Al of the Al(OiPr)2 group. 2. The second step presents the intermediate where the oxygen is protonated, and the Al carries a positive formal charge with a corresponding negative formal charge on oxygen. 3. The final step shows the departure of the Al(OiPr)2 group, leaving a double bond-forming product. **Option B:** 1. Like option A, the first step involves an attack from the oxygen lone pair on the Al of the Al(OiPr)2 group. 2. The intermediate structure also shows the oxygen protonated with charges similar to option A. 3. The final product formation matches what is shown in option A. **Option C:** 1. The first step is identical to options A and B with the oxygen lone pair attacking the Al of the Al(OiPr)2 group. 2. The intermediate correctly depicts the protonation with formal charges. 3. In the final product, the leaving of the Al(OiPr)2 group is illustrated, completing the mechanism properly. **Option D:** 1. The initial step mirrors the attack mechanism seen in previous options. 2. The intermediate is shown appropriately with correct formal charges. 3. The final product shows the departure of the Al(OiPr)2 group, forming the product structure correctly. **Conclusion:** All options show the same types of steps: initial oxygen lone pair attack on Al, intermediate formation with corresponding charges, and final product formation. However, option D shows the product forming in correct sequence and charge balance. Therefore, **Option D** illustrates the mechanism that is drawn correctly considering the arrows, formal charges, and intermediates. ### Diagram Explanation: - **Arrows:** Indicate the movement of electron pairs. Ensure that arrowheads point from electron donors (nucleophiles) to electron acceptors (electrophiles). - **Formal Charges:** Denoted on atoms for each intermediate, adhere to proper charge balance conservation through each step. - **Intermediates:** Transitional species appearing between the initial and final structures of the reactants and products. This analysis helps in understanding step-by-step reaction mechanisms crucial for learning organic
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