Which of the following lines is perpendicular to the equa y=-2x + 8 Ox+2y = 8 O x- 2y = 6 O 2x-y = 1 O 2x + y = 4

Elementary Geometry For College Students, 7e
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Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
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**Question: Identifying Perpendicular Lines**

**Which of the following lines is perpendicular to the equation \( y = -2x + 8 \)?**

**Equation:**
\[ y = -2x + 8 \]

**Options:**
1. \( \boxed{x + 2y = 8} \)
2. \( \boxed{x - 2y = 6} \)
3. \( \boxed{2x - y = 1} \)
4. \( \boxed{2x + y = 4} \)

**Explanation:**

To determine which line is perpendicular to \( y = -2x + 8 \), we need to find the line that has a slope that is the negative reciprocal of the slope of the given line. 

- The slope of the given line \( y = -2x + 8 \) is \( -2 \).

- The negative reciprocal of \( -2 \) is \( \frac{1}{2} \).

Therefore, the equation of the line perpendicular to \( y = -2x + 8 \) should have a slope of \( \frac{1}{2} \).

**Solving each option in slope-intercept form \( y = mx + b \) to find the slopes:**

1. \( x + 2y = 8 \)
   - Rearrange: \( 2y = -x + 8 \)
   - Divide by 2: \( y = -\frac{1}{2}x + 4 \)
   - Slope \( m = -\frac{1}{2} \) (Not correct)

2. \( x - 2y = 6 \)
   - Rearrange: \( -2y = -x + 6 \)
   - Divide by -2: \( y = \frac{1}{2}x - 3 \)
   - Slope \( m = \frac{1}{2} \) (Correct)

3. \( 2x - y = 1 \)
   - Rearrange: \( -y = -2x + 1 \)
   - Divide by -1: \( y = 2x - 1 \)
   - Slope \( m = 2 \) (Not correct)

4. \( 2x + y = 4 \)
   - Rearrange: \( y = -2x +
Transcribed Image Text:**Question: Identifying Perpendicular Lines** **Which of the following lines is perpendicular to the equation \( y = -2x + 8 \)?** **Equation:** \[ y = -2x + 8 \] **Options:** 1. \( \boxed{x + 2y = 8} \) 2. \( \boxed{x - 2y = 6} \) 3. \( \boxed{2x - y = 1} \) 4. \( \boxed{2x + y = 4} \) **Explanation:** To determine which line is perpendicular to \( y = -2x + 8 \), we need to find the line that has a slope that is the negative reciprocal of the slope of the given line. - The slope of the given line \( y = -2x + 8 \) is \( -2 \). - The negative reciprocal of \( -2 \) is \( \frac{1}{2} \). Therefore, the equation of the line perpendicular to \( y = -2x + 8 \) should have a slope of \( \frac{1}{2} \). **Solving each option in slope-intercept form \( y = mx + b \) to find the slopes:** 1. \( x + 2y = 8 \) - Rearrange: \( 2y = -x + 8 \) - Divide by 2: \( y = -\frac{1}{2}x + 4 \) - Slope \( m = -\frac{1}{2} \) (Not correct) 2. \( x - 2y = 6 \) - Rearrange: \( -2y = -x + 6 \) - Divide by -2: \( y = \frac{1}{2}x - 3 \) - Slope \( m = \frac{1}{2} \) (Correct) 3. \( 2x - y = 1 \) - Rearrange: \( -y = -2x + 1 \) - Divide by -1: \( y = 2x - 1 \) - Slope \( m = 2 \) (Not correct) 4. \( 2x + y = 4 \) - Rearrange: \( y = -2x +
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