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Which of the following is the solution of [2x + ycos(xy)]dx +xcos(xy)dy =0 a. x? +cos(xy)=c b. x? - 2cos(xy) = c %3D с. х? - 2sin(xy) - с d. x? + sin(xy) = c

Which of the following is the solution of [2x + ycos(xy)]dx +xcos(xy)dy =0 a. x? +cos(xy)=c b. x? - 2cos(xy) = c %3D с. х? - 2sin(xy) - с d. x? + sin(xy) = c

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Which of the following is the solution of [2x + ycos(xy)]dx +xcos(xy)dy = 0 a. x² +cos(xy)=c b. x² -2cos(xy) = c COS COS %3D с. х? - 2 sin(xy) - с d. x² + sin(xy) = c ху) — ху
Transcribed Image Text:Which of the following is the solution of [2x + ycos(xy)]dx +xcos(xy)dy = 0 a. x² +cos(xy)=c b. x² -2cos(xy) = c COS COS %3D с. х? - 2 sin(xy) - с d. x² + sin(xy) = c ху) — ху
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