Which of the following is the general solution of the linear system 1 x ? -2 -2 Lütfen birini seçin: x1(t) = (c1 cos t - c2 sin t)e¬t 12(t) = [c1(cost – sin t) + c2(sin t + cos t)]e=t 1(t) = (c1 cos t +c2 sin t)e r2(t) = [c1(cos t + sin t) + c2(sin t – cos t)]e¬t x1(t) = (c1 cos 2t + c2 sin 2t)e' r2(t) = [c1(cos 2t – 2 sin 21) + c2(sin 2t + 2 cos 2t)]e" 1(t) = (c1 cos t + c2 sin t)e¬ r2(t) = [-c1 (cos t + sin t) + c2(cos t – sin t)]e¯t %3D
Which of the following is the general solution of the linear system 1 x ? -2 -2 Lütfen birini seçin: x1(t) = (c1 cos t - c2 sin t)e¬t 12(t) = [c1(cost – sin t) + c2(sin t + cos t)]e=t 1(t) = (c1 cos t +c2 sin t)e r2(t) = [c1(cos t + sin t) + c2(sin t – cos t)]e¬t x1(t) = (c1 cos 2t + c2 sin 2t)e' r2(t) = [c1(cos 2t – 2 sin 21) + c2(sin 2t + 2 cos 2t)]e" 1(t) = (c1 cos t + c2 sin t)e¬ r2(t) = [-c1 (cos t + sin t) + c2(cos t – sin t)]e¯t %3D
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
![Which of the following is the general solution of the
linear system
1
x ?
-2 -2
Lütfen birini seçin:
r1(t) = (c1 cos t – c2 sin t)e
12(t) = [c1(cost - sin t) + c2(sint + cos t)]e¬t
1(t) = (c1 cos t + c2 sin t)e¬
r2(t) = [c1(cos t + sin t) + c2(sin t – cos t)]et
z1(t) = (c1 cos 2t + c2 sin 2t)e'
r2(t) = [c1(cos 2t – 2 sin 21)
+ c2(sin 2t + 2 cos 2t)]e*
1(t) = (c1 cos t +c2 sin t)e¬
r2(t) = [-c1(cost + sin t) + c2(cos t – sin t)]e¬
11(t) = (c1 cost – c2 sin t)et
r2(t) = [c1(cos t– 2 sin t) +c2(sin t+2 cos t)]e=
%3D
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffc0c798c-3f36-4490-a695-0a92fc2b731a%2F00d498ac-72ff-4e2a-9633-70e2b4db8d82%2Fsro0m3g_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Which of the following is the general solution of the
linear system
1
x ?
-2 -2
Lütfen birini seçin:
r1(t) = (c1 cos t – c2 sin t)e
12(t) = [c1(cost - sin t) + c2(sint + cos t)]e¬t
1(t) = (c1 cos t + c2 sin t)e¬
r2(t) = [c1(cos t + sin t) + c2(sin t – cos t)]et
z1(t) = (c1 cos 2t + c2 sin 2t)e'
r2(t) = [c1(cos 2t – 2 sin 21)
+ c2(sin 2t + 2 cos 2t)]e*
1(t) = (c1 cos t +c2 sin t)e¬
r2(t) = [-c1(cost + sin t) + c2(cos t – sin t)]e¬
11(t) = (c1 cost – c2 sin t)et
r2(t) = [c1(cos t– 2 sin t) +c2(sin t+2 cos t)]e=
%3D
%3D
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