Which of the following is NOTa vector quantity? O force impulse O all of the given quantities are vectors O displacement momentum O velocity O acceleration
Which of the following is NOTa vector quantity? O force impulse O all of the given quantities are vectors O displacement momentum O velocity O acceleration
College Physics
1st Edition
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:Paul Peter Urone, Roger Hinrichs
Chapter8: Linear Momentum And Collisions
Section: Chapter Questions
Problem 3PE: (a) At what speed would a 2.00104 -kg airplane have to fly to have a momentum of 1.60109kgm/s (the...
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Transcribed Image Text:**Question:**
Which of the following is NOT a vector quantity?
- ○ force
- ○ impulse
- ○ all of the given quantities are vectors
- ○ displacement
- ○ momentum
- ○ velocity
- ○ acceleration
![**Problem Statement:**
A hockey puck (mass = 200 grams) is gliding on perfectly smooth (frictionless) ice at 10 m/s to the West. What is the momentum of the puck?
**Options:**
- ○ zero, since it is not changing speed
- ○ 20 \((\text{kg} \cdot \frac{\text{m}}{\text{s}})\) West
- ○ 2000 \((\text{kg} \cdot \frac{\text{m}}{\text{s}})\) West
- ○ 200 \((\text{kg} \cdot \frac{\text{m}}{\text{s}})\) West
- ○ 2 \((\text{kg} \cdot \frac{\text{m}}{\text{s}})\) West
**Explanation:**
To calculate the momentum (\( p \)) of the puck, use the formula:
\[ p = m \times v \]
where \( m \) is the mass in kilograms and \( v \) is the velocity in meters per second.
First, convert the mass from grams to kilograms:
\[ 200 \text{ g} = 0.2 \text{ kg} \]
Then, plug the values into the formula:
\[ p = 0.2 \text{ kg} \times 10 \text{ m/s} = 2 \text{ kg} \cdot \frac{\text{m}}{\text{s}} \]
Therefore, the correct answer is:
- ○ 2 \((\text{kg} \cdot \frac{\text{m}}{\text{s}})\) West](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe815d996-ac78-4584-a71e-4284151c4e48%2F02b853de-cce9-42c1-a093-77d27ad058f9%2F3xobs1r_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
A hockey puck (mass = 200 grams) is gliding on perfectly smooth (frictionless) ice at 10 m/s to the West. What is the momentum of the puck?
**Options:**
- ○ zero, since it is not changing speed
- ○ 20 \((\text{kg} \cdot \frac{\text{m}}{\text{s}})\) West
- ○ 2000 \((\text{kg} \cdot \frac{\text{m}}{\text{s}})\) West
- ○ 200 \((\text{kg} \cdot \frac{\text{m}}{\text{s}})\) West
- ○ 2 \((\text{kg} \cdot \frac{\text{m}}{\text{s}})\) West
**Explanation:**
To calculate the momentum (\( p \)) of the puck, use the formula:
\[ p = m \times v \]
where \( m \) is the mass in kilograms and \( v \) is the velocity in meters per second.
First, convert the mass from grams to kilograms:
\[ 200 \text{ g} = 0.2 \text{ kg} \]
Then, plug the values into the formula:
\[ p = 0.2 \text{ kg} \times 10 \text{ m/s} = 2 \text{ kg} \cdot \frac{\text{m}}{\text{s}} \]
Therefore, the correct answer is:
- ○ 2 \((\text{kg} \cdot \frac{\text{m}}{\text{s}})\) West
Expert Solution

Step 1
Given
Part-1: physical quantities is mentioned in a option
We have to choose the which quantity or quantities not a vector quantities
Part-2:
Mass of hockey puck = 200 g = 0.200 kg
Velocity of hockey puck = 10 m/s towards west
We have to calculate momentum of the hockey puck
Step by step
Solved in 2 steps

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