Part AWhich of the following is equal to exactly Avogadro's number of atoms?O 36.00 grams of kryptonO 31.93 grams of cobalt8.00 grams of oxygenO 12.01 grams of carbonO 12.31 grams of magnesiumSubmitRequest AnswerscarF3FA%233.

We have given that Which of the following is equal to exactly Avogadro's number of atoms? A. 36.00 grams of krypton B. 31.93 grams of cobalt C .8.00 grams of oxygen D. 12.01 grams of carbon E. 12.31 grams of magnesiumWe know that Avogadros number is the number of units in one mole of any substance equal to 6.022 × 1023 We know that 1 mole of any substance is defined as its molecular weight of the Substance. A. 36.00 grams of krypton Ans : Molar mass of Krypton = 83.798g/mole Moles of Krypton = ( 36g ) / (83.798g/mole) = 0.4296 mole No.of atom of Krypton = 0.4296 mole × 6.022 × 1023 mol-1 = 2.587 × 1023 atoms of Krypton B. 31.93 grams of Cobalt Ans : Molar mass of Cobalt = 58.9332g/mole Moles of Cobalt = ( 31.93g ) / (58.9332g/mole) = 0.5418 mole No.of atom of Cobalt = 0.5418 mole × 6.022 × 1023 mol-1 = 3.263 × 1023 atoms of Cobalt C .8.00 grams of Oxygen Ans : Molar mass of Oxygen = 16.0g/mole Moles of Oxygen = ( 8.0g ) / (16.0g/mole) = 0.5 mole No.of atom of Oxygen = 0.5 mole × 6.022 × 1023 mol-1 = 3.011 × 1023 atoms of Oxygen D. 12.01 grams of Carbon Ans : Molar mass of Carbon = 12.01g/mole Moles of Carbon = ( 12.01g ) / (12.01g/mole) = 1 mole No.of atom of Carbon = 1 mole × 6.022 × 1023 mol-1 = 6.022 × 1023 atoms of Carbon E. 12.31 grams of Magnesium Ans : Molar mass of Magnesium = 24.305g/mole Moles of Magnesium = ( 12.31g ) / (24.305g/mole) = 0.5065 mole No.of atom of Magnesium = 0.5065 mole × 6.022 × 1023 mol-1 = 3.05 × 1023 atoms of Magnesium 12.01g of Carbon = 6.022 × 1023 atoms of Carbon. Therefore 12.01g of Carbon is equal to exactly Avogadro's number of atoms.

Answered: Which of the following is equal to…

Science

Chemistry

Which of the following is equal to exactly Avogadro's number of atoms? O 36.00 grams of krypton 31.93 grams of cobalt O 8.00 grams of oxygen O 12.01 grams of carbon O 12.31 grams of magnesium

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

1.00 mole of copper(II) sulfate, CuSO4, contains how many O atoms? O 2.41 x 1023 O atoms 2.41 x 1024 O atoms O 6.02 x 1023 O atoms O 1.51 x 1023 O atoms
How many oxygen atoms are there in 52.06 g of carbon dioxide? O 6.022 x 1023 5.088 x 1023 1.422 x 1024 3.519 x 1023 1.018 x 1024
the molar mass of ca3(po4)2 is 310.18 g/mol) calculate the grams of ca if there are 253 grams of ca3(po4)2
I need help with understanding the equation and how it's broken down
How much, in grams, does each of the following quantities of matter weigh? a) 5.00 moles of Cl atoms grams of Cl b) 5.00 moles of Cl2 molecules grams of Cl2
How many atoms are contained in 12 g of water? 2.4 x 1024 1.2 x 1024 4.0 x 1023 O 1.3 x 1023
How many moles of Ag2SO4 are in a sample that contains 1.06 x 1023 molecules? How many grams are in this sample?
How many hydrogen atoms are in 5.0 g of citric acid (Có H&O7)? O 1.6 × 10² Hydrogen atoms O 4.6 x 10²7 Hydrogen atoms O 1.8 × 1026 Hydrogen atoms O 1.3 × 10²3 Hydrogen atoms
Which sample has the greatest amount of atomic nitrogen? 2.0 mol of NO2 3.01 × 1023 molecules of N2 33.0 g of N2O
How many atoms of carbon are in 9.0g of C6H1206? 6 1.81 x 1023 4.9 x 1023 O 3.01 x 1023
How many atoms of calcium are contained in 112.0 grams of calcium? O 6.745 x 1025 O 7.454 x 1021 O 1.683 x 1024 O 16.8279 x 1023 O 4.640 x 10-24
Consider separate 100.0-g samples of each of the following: NH3, N₂O, HCN, N₂H4, and HNO3. Which of the samples has the greatest mass of nitrogen? N₂O N₂H4 HCN HNO3 NH3