Which of the following is an example of a series such that Σa, converges but Σa, diverges? Α.Σ (1) 3 n Β.Σ(-1)"3η C.Y (-1)" √√n D.Σn-3

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Question**: Which of the following is an example of a series such that \(\sum a_n\) converges but \(\sum |a_n|\) diverges?

**Options**:

A. \(\sum \frac{(-1)^n}{n^3}\)

B. \(\sum \frac{(-1)^{n^{3}}}{\sqrt{n}}\)

C. \(\sum \frac{(-1)^n}{\sqrt[3]{n}}\)

D. \(\sum n^{-3}\)

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### Explanation of the Problem

This problem is asking for an example of an alternating series that converges, but whose corresponding series of absolute values diverges. This touches on the concept of conditional and absolute convergence in series.

1. **Conditional Convergence**: A series \(\sum a_n\) is conditionally convergent if it converges but the series of absolute values \(\sum |a_n|\) diverges. This often occurs in alternating series.
  
2. **Absolute Convergence**: A series \(\sum a_n\) is absolutely convergent if \(\sum |a_n|\) converges.

---

### Series Analysis

To determine which series meets the criteria, let's analyze each option:

#### Option A: 
\(\sum \frac{(-1)^n}{n^3}\)

This is an alternating series of the form \(\sum (-1)^n b_n\) where \(b_n = \frac{1}{n^3}\). For the alternating series test (Leibniz’s Test), we need:
- \(b_n\) is positive,
- \(b_n\) is decreasing,
- \(\lim_{n \to \infty} b_n = 0\).

All conditions are met because \(\frac{1}{n^3}\) is positive, decreasing, and approaches 0 as \(n\) approaches infinity. Hence, \(\sum \frac{(-1)^n}{n^3}\) converges.

For absolute convergence, we need to check \(\sum \left| \frac{(-1)^n}{n^3} \right| = \sum \frac{1}{n^3}\). Since \(\frac{1}{n^3}\) is a p-series with \(p = 3 > 1\), it converges.

#### Option B:
\
Transcribed Image Text:**Question**: Which of the following is an example of a series such that \(\sum a_n\) converges but \(\sum |a_n|\) diverges? **Options**: A. \(\sum \frac{(-1)^n}{n^3}\) B. \(\sum \frac{(-1)^{n^{3}}}{\sqrt{n}}\) C. \(\sum \frac{(-1)^n}{\sqrt[3]{n}}\) D. \(\sum n^{-3}\) --- ### Explanation of the Problem This problem is asking for an example of an alternating series that converges, but whose corresponding series of absolute values diverges. This touches on the concept of conditional and absolute convergence in series. 1. **Conditional Convergence**: A series \(\sum a_n\) is conditionally convergent if it converges but the series of absolute values \(\sum |a_n|\) diverges. This often occurs in alternating series. 2. **Absolute Convergence**: A series \(\sum a_n\) is absolutely convergent if \(\sum |a_n|\) converges. --- ### Series Analysis To determine which series meets the criteria, let's analyze each option: #### Option A: \(\sum \frac{(-1)^n}{n^3}\) This is an alternating series of the form \(\sum (-1)^n b_n\) where \(b_n = \frac{1}{n^3}\). For the alternating series test (Leibniz’s Test), we need: - \(b_n\) is positive, - \(b_n\) is decreasing, - \(\lim_{n \to \infty} b_n = 0\). All conditions are met because \(\frac{1}{n^3}\) is positive, decreasing, and approaches 0 as \(n\) approaches infinity. Hence, \(\sum \frac{(-1)^n}{n^3}\) converges. For absolute convergence, we need to check \(\sum \left| \frac{(-1)^n}{n^3} \right| = \sum \frac{1}{n^3}\). Since \(\frac{1}{n^3}\) is a p-series with \(p = 3 > 1\), it converges. #### Option B: \
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