Which of the following integrals will correctly solve for the force a circular conductor with radius 4.20 m a center at origin experiences if the magnetic field in the region is given as B = coso (cose – sine) a, – sine coso ag + r(sin20 – e-' cos2e) a T? The circular conductor lies on = 90°, and carries current of 6.9 A in the D-direction. O The answer cannot be found on the other choices. -6.9 eJ (cosø a@ - cosø a,)(4.20)² dộ 2m -6.9) (cosø a@ - cosø a,) do -6.9 (cosø ae - coso a,) 4.20 dộ
Which of the following integrals will correctly solve for the force a circular conductor with radius 4.20 m a center at origin experiences if the magnetic field in the region is given as B = coso (cose – sine) a, – sine coso ag + r(sin20 – e-' cos2e) a T? The circular conductor lies on = 90°, and carries current of 6.9 A in the D-direction. O The answer cannot be found on the other choices. -6.9 eJ (cosø a@ - cosø a,)(4.20)² dộ 2m -6.9) (cosø a@ - cosø a,) do -6.9 (cosø ae - coso a,) 4.20 dộ
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Transcribed Image Text:Which of the following integrals will correctly solve for the force a circular conductor with radius 4.20 m and
center at origin experiences if the magnetic field in the region is given as
B = coso (cose - sine) a, – sine coso a, + r(sin20 – e-ľ cos2e) ao
conductor lies on e = 90°. and carries current of 6.9 A in the 0-direction.
T? The circular
The answer cannot be found on the other choices.
-6.9
J (cosøa@ - cosø a,)(4.20)² dø
-6.9 (coso ae - coso a,) do
-6.9
1 (cosoae - coso a,) 4.20 do
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