Which of the following hypotheses indicates expected increases based on an independent variable? Non-directional hypothesis Directional hypothesis
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Which of the following hypotheses indicates expected increases based on an independent variable?
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Non-directional hypothesis
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Directional hypothesis
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- A study of sleeping hours of students in Ohio State University recorded sleeping hours of 45 random sample with mean 6 hours and standard deviation 1.2. Suppose we recorded sleeping hour of a new students, can you predict the upper bound of 95% prediction interval of the new student's sleeping hours? 8.45 9.23 7.55 6.80What is the value of the t-statistic used to test the null hypothesis of zero slope via a t-test? Please put the answer in bold.Q2) Independent-Samples t-Test (Round calculated results to the hundredth (2nd place to the right of the decimal)) In a research project, researchers collected demographic and health data from a sample of elderly residents in the community. To examine any possible gender differences in their sample, they want to see if the females and the males differ significantly on the education level (number of years of formal schooling). The researchers are not predicting any direction in the possible gender differences so the hypotheses should be non-directional. They would like to run a two-tailed test with α = .10. Male Subject ID Education Female Subject ID Education 1 14 13 14 2 15 14 15 3 17 15 18 4 13 16 18 5 15 17 16 6 15 18 17 7 13 19 16 8 15 20 16 9 15 21 17 10 16 22 15 11 17…
- Is the length of time of unemployment related to the type of industry? A random sample of unemployed workers from three different work sectors yielded the following data. Perform a hypothesis test at 0.10 level of significance to determine if there is a relationship. Less than 5 weeks 5-14 weeks 15-26 weeks Transportation 89 115 77 Information 64 65 43 Financial 80 113 114 What are the expected numbers? (round to 3 decimal places) Less than 5 weeks 5-14 weeks 15-26 weeks Transportation Information Financial The hypotheses are H0:H0: The length of unemployment is independent of the type of industry. HA:HA: The length of unemployment is dependent of the type of industry. (claim) Since αα = 0.10 the critical value is 7.779 The test value is: (round to 3 decimal places) The p-value is (round to 3 decimal places) So the decision is to reject H0H0 do not reject H0H0 Thus the final conclusion is There is not enough…Test the claim that the mean GPA of night students is smaller than 2.5 at the 10% significance level. The population standard deviation for this group is known to be 0.16. The null and alternative hypotheses for this test are: Но: д 2.5 Нд:д > 2.5 НА:Д < 2.5 The test is: left-tailed right-tailed Based on a sample of 30 people, the sample mean GPA was 2.47. Hint: Before you find the p-value below, calculate the test statistic to two decimal places. The p-value is: (to 4 decimals) The significance level as a decimal is: Based on this we O fail to reject the null hypothesis, Ho O reject the null hypothesis, HoWhat is a Type II error? a. Ho is rejected and there is an effect b. Ho is rejected but there is no effect c. Ho is retained but there is an effect d. The wrong standard deviation is calculated.
- Explain seven steps in hypothesis testing for Coca Cola net income averaged $40 million per year with a standard deviation of $15 million(n=6 observations). Management claims that Coca Cola performance during the most recent cycle results from new approaches and that they should dismiss profitability expectations based on its average or normalized earnings of $34million per year in prior cycles.6.18 Is college worth it? Part II: Exercise 6.16 presents the results of a poll where 48% of 331 Americans who decide to not go to college do so because they cannot afford it.(a) Calculate a 90% confidence interval for the proportion of Americans who decide to not go to college because they cannot afford it, and interpret the interval in context.lower bound:__________ (please round to four decimal places)upper bound:__________ (please round to four decimal places) Interpret the confidence interval in context: ______ We can be 90% confident that the proportion of Americans who choose not to go to college because they cannot afford it is contained within our confidence interval ______ 90% of Americans choose not to go to college because they cannot afford it _______ We can be 90% confident that our confidence interval contains the sample proportion of Americans who choose not to go to college because they cannot afford it (b) Suppose we wanted the margin of error for the 90%…Partially Correct (a): Your answer is incorrect. Students at a major university are complaining of a serious housing crunch. They complain that many students have to commute too far to school because there is not enough housing near campus. University officials respond with the following information: the mean distance commuted to school by students is 15.0 miles, and the standard deviation of the distance commuted is 3.9 miles. Assuming that the university officials' information is correct, complete the following statements about the distribution of commute distances for students at this university.
- Test the claim that the mean amount of debt that students carry is greater than or equal to $21,000. Use a significance of .12. The sample of 140 students gave a mean of -13987 and a standard deviation of $2337. Claim: [Select] Null Hypothesis Ho:μ Alternative Hypothesis HA: [Select] test statistic t= [Select] P value=[Select] [Select] We [Select] The data [Select] + [Select] + [Select] + (reject/fail to reject) Ho + (One of these , , , and then a number) [Select] + (Three decimals like -4.976) (One of these , , , and then a number) (One of these ,=,, and then a number) (supports/fails to support/rejects/fails to reject) the claim that the mean is less than 3.It is believed that nearsightedness affects about 8% of all children. In a random sample of 220 children, 26 are nearsighted.(a) Construct hypotheses appropriate for the following question: do these data provide evidence that the 8% value is inaccurate? __Ho: p = .08Ha: p > .08 __Ho: p = .08Ha: p < .08 __Ho: p = .08Ha: p ≠ .08 (b) What proportion of children in this sample are nearsighted? _______ (round to four decimal places)(c) Given that the standard error of the sample proportion is 0.0195 and the point estimate follows a nearly normal distribution, calculate the test statistic. Z = _______ (round to two decimal places)(d) What is the p-value for this hypothesis test? P-value = __________ (round to four decimal places) (e) What is the conclusion of the hypothesis test? Since p ≥ α we do not have enough evidence to reject the null hypothesis Since p<α we reject the null hypothesis and accept the alternative Since p ≥ α we accept the null hypothesis Since p ≥ α we reject…An ANOVA provides the following data: Degrees of freedom between groups is 2; degrees of freedom within groups is 27; F- obt is 3.31 What is the correct statistical conclusion here? (hint: you'll need to find F-crit before you answer) O We fail to reject the null hypothesis and conclude that there is a significant difference among the groups' means O We reject the null hypothesis and conclude that there is a significant difference among the groups' means O We fail to reject the null hypothesis and conclude that there is no significant difference among the groups' means O We reject the null hypothesis and conclude that there is no significant difference among the groups' means